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Bad White [126]
3 years ago
14

Friction is the resistance to motion that occurs when one material slides across another material. All materials have surface ir

regularities and are not perfectly smooth.
As the materials move, the irregularities get caught on one another requiring more force. Friction wears down a surface while producing heat, such as tires on a road or skin receiving a rug burn from sliding across carpet.

1. Why would someone rub their hands together really fast when they are cold?

2. Give another example of friction that was not discussed above.
Physics
2 answers:
Leona [35]3 years ago
8 0
Friction causes heat, rubbing your hands together thus gives off heat. Another example of friction is the tires of your car. As they go along the rough surface of the pavement they cause friction, eventually stopping your vehicle and giving off heat.
Sophie [7]3 years ago
6 0
The answer to number one is to produce heat.
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allsm [11]
-3.5mls squared = a

0mls = 21mls + a(6s)
-21mls/6s

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4 0
3 years ago
Jane has four glasses of milk. The temperature and the amount of milk in each glass are shown:
SOVA2 [1]

The molecules of milk in Glass B have greater kinetic energy than the molecules of milk in Glass D.

6 0
3 years ago
Three-point charges are arranged on a line. Charge q3 = +5.00nC and is at the origin. Charge q2 = -3.00 nC and is at x = 5.00 cm
Anon25 [30]

Answer:

Explanation:

Given

Charge q_3=+5\ nC is placed at origin

Charge q_2=-3\ nC is placed at x=5\ cm

Charge q_1 is Placed at x=2.5\ cm

charge q_1 must be positive so as to balance the force on charge q_3

Force on q_3 due to q_1 is

F_{31}=\frac{kq_1q_3}{r^2}

here r=2.5\ cm

F_{31}=\frac{kq_1q_3}{(2.5)^2}

Force on q_3 due to q_2 is

F_{32}=\frac{kq_3q_2}{r^2}

here r=5\ cm

F_{32}=\frac{kq_3q_2}{(5)^2}

F_{31}=F_{32}

\frac{kq_1q_3}{(2.5)^2}=\frac{kq_3q_2}{(5)^2}

q_1=q_2(\frac{2.5}{5})^2

q_1=3\times (\frac{2.5}{5})^2

q_1=3\times \frac{1}{4}

q_1=0.75\ nC

                                                                   

5 0
4 years ago
Which of the following explains how electricity flows?
Yuri [45]
Electrons flow from the positive end of a source towards the negative end
7 0
3 years ago
100 g of Ice at -10°C is added into a
Andrei [34K]

Answer:

The mass of the juice responsible for melting the ice is 949.043 grams.

Explanation:

By the First Law of Thermodynamics, we understand that juice releases heat to the ice, which turns into water under the assumption that interactions between the ice-juice system and surroundings are negligible and energy processes are done in steady-state. Since juice is done with water, its specific heat will be taken as of the water. The process is described by the following formula:

m_{i} \cdot [c_{i}\cdot (T_{1}-T_{2}) - L_{f} + c_{w}\cdot (T_{2}-T_{3})] + m_{w} \cdot  c_{w}\cdot (T_{4}-T_{3}) = 0 (1)

Where:

m_{i} - Mass of ice, in grams.

m_{w} - Mass of the juice, in grams.

c_{i} - Specific heat of ice, in joules per gram-degree Celsius.

c_{w} - Specific heat of water, in joules per gram-degree Celsius.

L_{f} - Latent heat of fusion, in joules per gram.

T_{1} - Initial temperature of ice, in degrees Celsius.

T_{2} - Melting point of water, in degrees Celsius.

T_{3} - Final temperature of the ice-juice system, in degrees Celsius.

T_{4} - Initial temperature of the juice, in degrees Celsius.

If we know that m_{i} = 100\,g, c_{i} = 2.090\,\frac{J}{g\cdot ^{\circ}C}, c_{w} = 4.18\,\frac{J}{g\cdot ^{\circ}C}, L_{f} = 334\,\frac{J}{g}, T_{1} = -10\,^{\circ}C, T_{2} = 0\,^{\circ}C, T_{3} = 10\,^{\circ}C and T_{4} = 20\,^{\circ}C, then the mass of the juice is:

m_{w} = \frac{m_{i}\cdot [c_{i}\cdot (T_{1}-T_{2}) - L_{f} + c_{w}\cdot (T_{2}-T_{3})]}{c_{w} \cdot (T_{3}-T_{4})}

m_{w} = \frac{(100\,g)\cdot  \left[\left(2.090\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (-10\,^{\circ}C) - 334\,\frac{J}{g} +\left(4.18\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (-10\,^{\circ}C)  \right]}{\left(4.180\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (-10\,^{\circ}C)}

m_{w} = 949.043\,g

The mass of the juice responsible for melting the ice is 949.043 grams.

5 0
3 years ago
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