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Aleks04 [339]
3 years ago
9

When a mule stops suddenly, the packages

Physics
1 answer:
Flauer [41]3 years ago
5 0
The answer here would be the first law of motion. An object in motion will stay in motion unless acted upon by another force.
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Need help anybody thanks
mars1129 [50]
If there are no windows, then the illumination in the room depends
only on the room and what's in it, not on anything outside. 
The time of day has no effect.  The other things all do. 
4 0
3 years ago
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
bazaltina [42]

Answer:

The current in the rods is 171.26 A.

Explanation:

Given that,

Length of rod = 0.85 m

Mass of rod = 0.073 kg

Distance d = 8.2\times10^{-3}\ m

The rods carry the same current in the same direction.

We need to calculate the current

I is the current  through each of the wires then the force per unit length on each of them is

Using formula of force

\dfrac{F}{L}=\dfrac{\mu_{0}I^2}{2\pi d}

\dfrac{mg}{L}=\dfrac{\mu_{0}I^2}{2\pi d}

Where, m = mass of rod

l = length of rod

Put the value into the formula

I^2=\dfrac{mgd}{\mu L}

I^2=\dfrac{0.073\times9.8\times8.2\times10^{-3}}{2\times10^{-7}}

I=\sqrt{29331.4}

I=171.26\ A

Hence, The current in the rods is 171.26 A.

5 0
3 years ago
Determine the magnitude of the resultant force FR=F1+F2FR=F1+F2. Assume that F1F1F_1 = 235 lblb and F2F2F_2 = 350 lb
Svetlanka [38]

Answer:

<em>585lb</em>

Explanation:

Given the formula for calculating the magnitude of the resultant force as;

F_R = F_1 + F_2

<em>Given </em>

<em></em>F_1 = 235 lb \ and \ F_2 = 350 lb\\F_R = 235lb + 350lb\\F_R = 585lb\\<em></em>

<em>Hence the magnitude of the resultant force is 585lb</em>

4 0
3 years ago
Water drips from a faucet at the rate of 150 drops in 120 seconds. What is the period?
user100 [1]

Answer:

.80

Explanation:

7 0
3 years ago
I NEED HELP WITH THE LAST QUESTION PLS HELP!! (The one below 8)
maksim [4K]

Answer:

I. 6 cells .

II. Series connection.

Explanation:

I. Determination of the number of cells needed.

From the question given above,

Total voltage (V) = 9 V

1.5 V = 1 cell

Number of cells needed =?

The number of cells needed to make the 9V battery can be obtained as follow:

1.5 V = 1 cell

Therefore,

9 V = 9 V × 1 cell / 1.5 V

9 V = 6 cells

Thus, 6 cells of 1.5 V each is needed

II. Determination of the connection line

Total voltage (Vₜ) = 9 V

Cell 1 (V₁) = 1.5 V

Cell 2 (V₂) = 1.5 V

Cell 3 (V₃) = 1.5 V

Cell 4 (V₄) = 1.5 V

Cell 5 (V₅) = 1.5 V

Cell 6(V₆ ) = 1.5 V

For parrall connection:

Vₜ = V₁ = V₂ = V₃ = V₄ = V₅ = V₆

9 V = 1.5 V =... = 1.5 V

For series connection:

Vₜ = V₁ + V₂ + V₃ + V₄ + V₅ + V₆

9 = 1.5 + 1.5 + 1.5 + 1.5 + 1.5 + 1.5

9 V = 9 V

From the illustration above, we can see that series connection of each cells will give a total volt of 9 V unlike the parallel connection which resulted to 1.5 V.

Therfore, the cells should be arranged in series connection

8 0
3 years ago
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