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3 years ago

If a function f is increasing on (a,

Mathematics

1 answer:

pashok25 [27]3 years ago

8 0

If the function is continuous on (a,c), it has a maximum at b. if it is not continuous, nothing can be said.

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Can anyone help me. Will give you all my points and brainliest:)

PilotLPTM [1.2K]

See the attachments for the answer :)

8 0

3 years ago

A sample poll of 100 voters were chosen from a given district<br>

Julli [10]

Answer:

5y345

Step-by-step explanation:

i did it before

6 0

2 years ago

(Giving brainliest! Pls have at least one sentence to explain why you chose the answer :) )

Kryger [21]

Answer:

Step-by-step explanation:

Hope it helps

4 0

3 years ago

Read 2 more answers

The trip took 1 hour and 40 minutes 30% of the time the car traveled on rough roads how much time did the car travel on rough ro

Effectus [21]

Answer:

NOTE: 1 HOUR IS 60 MINUTES

do 60+40 gives u the minute which is 100

then 100 x30% = 30

NOTE: for the second round up the digit and multiply it by 65

so 40.4 x 65 gives 62. something

the nearest number is 60 % so 60% is the answer

<em>Please mark as brainliest</em>

Have a great day, be safe and healthy

Thank u

4 0

3 years ago

Read 2 more answers

The gross weight of a truck containing 30 pigs is 8 tons 1,123 pounds and 6 ounces. The average weight of one pig is 95 pounds 1

irakobra [83]

Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

The weight of the empty truck is 7 tons 254 pounds 10 ounces.

Step-by-step explanation:

Since we have given that

The gross weight of a truck containing 30 pigs = 8 tons 1123 pounds 6 ounces

Average weight of one pig = 95 pounds 10 ounces

Now,

We know that

$1\text{ pound}=16\text{ ounces}$

So,

$\text{Gross weight of truck containing 30 pigs}\\=8\text{ tones }1123\times 16+6\text{ ounces}\\=8\text{ tons }17974\text{ ounces}$

Similarly,

$\text{ average weight of one pig }\\=95\times 16+10\text{ ounces}\\=1530\text{ ounces}$

So, Net weight of the pigs in the truck

$1530\times 30\\ =45900\text{ ounces}\\\\=\frac{45900}{16}\\\\=2868\text{ pounds }12\text{ ounces}\\\\=1\text{ ton }868\text{ pounds }12\text{ ounces }$

So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

Now, we'll find the weight of the empty truck is given by

$\text{Gross weight of a truck containing} -\text{ Net weight of pigs in the truck}\\=8\text{ tons}1123\text{ pounds}6\text{ ounces}-1\text{ton }868\text{ pounds }12\text{ounces}\\=(8\times 2000\times 16+1123\times 16+6)-(1\times 2000\times 16+868\times 16-12)\\=273974\text{ ounces}-45900\text{ ounces}\\=228074\text{ounces }\\=7\text{ tons }254\text{ pounds }10\text{ ounces}$

Hence, the weight of the empty truck is 7 tons 254 pounds 10 ounces .

4 0

3 years ago