Question

A coordinate plane with a line passing through (negative 3, 2) and (0, 3)

Answer 1

Let's check

$\\ \sf\longmapsto Slope=m=\dfrac{3-2}{0+3}=\dfrac{1}{3}$

• Y intercept is 3✓

Now

let f(x) be y

$\\ \sf\longmapsto y=mx+b$

$\\ \sf\longmapsto y=\dfrac{1}{3}x+3=f(x)\checkmark$

Answer 2

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Let's find the slope (m) of given line :

• $\dfrac{y_2 - y_1}{x_2 - x_1}$

• $\dfrac{3 - 2}{0 - ( - 3 )}$

• $\dfrac{1}{3}$

Hence, The slope of the line is

✔ 1/3

y - intercept (c) is the value of y, when x = 0

or y - coordinate of point at which the line

cuts y - axis.

that is : 3 ✔

the linear function represented by the graph is :

• $f(x) = \dfrac{1}{3} x + 3$