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3 years ago

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A 25-year-old sexually active female presents with urethritis, dysuria, and cervical discharge. she is diagnosed with the most c

ommon bacteria sti in the united states. the student would identify this infection is due to: a. gonorrhea b. syphilis c. chlamydia d. herpes

1 answer:

atroni [7]3 years ago

4 0

The answer to this question is b syphillis because of cervical discharge

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A rooster with gray feathers is mated with a hen of the same phenotype. Among their offspring, 15 chicks are gray, 6 are black,

m_a_m_a [10]

Answer:

Alleles for feather colour exhibit incomplete dominance or co-dominance.

50% gray offspring + 50% black offspring

Explanation:

<em>It means that the alleles for feather colour in the hen exhibit incomplete dominance or co-dominance over one another.</em>

Assuming the allele for white colour is B, white colour will be b while the heterozygote Bb gives the gray phenotype.

Gray rooster + gray hen = 15 gray chicks, 6 black chicks and 8 white chicks.

15:6:8 is roughly 2:1:1 which is phenotypic ratio obtainable from crossing two heterozygous individuals as pointed out by Mendel.

Bb x Bb = 1BB, 2Bb, and 1bb

Crossing the gray rooster (Bb) with a black hen (bb):

Bb x bb = Bb, Bb, bb, and bb

= 2Bb (gray):2bb (black)

50% of the offspring will be gray while the remaining 50% will be black.

7 0

3 years ago

Which statement best explains why invertebrates often have outer skeletons but vertebrates do not?

quester [9]

The outer skeleton provides protection due to the fact that invertebrates do not have backbones

8 0

3 years ago

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A group of students are walking in the park and one of them takes a picture of a pollen grain that is being blown by the wind. W

nata0808 [166]

<span>gene mutation in action gene flow at work genetic drift as it happens natural selection in progress.</span>

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3 years ago

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In humans, dimples (D) are dominant over no dimples (d). Curly hair (A) is dominant over

jeyben [28]

Answer:

1. ddaa

2. DdAa

3. One from each parent

4. False

5. 0.25

6. 0.25

7. 0.25

8. 0.5

Explanation:

The remaining part of the question is

1. What is Jane's genotype?

2. What is Paul’s genotype?

3. Where did Jane get her gene for curly hair? From her mother or father?

4. True or False: Jane's mother was heterozygous for curly hair?

5. What fraction of Paul and Jane's children should have curly hair and dimples?

6. What fraction of their children would have straight hair and no dimples?

7. What fraction should have dimples but not curly hair?

8. What is the probability of getting any offspring with dimples

Solution

1. Genotype of Jane's mother -ddaa

2. Genotype of Paul (heterozygous for dimples and curly hair) – DdAa

3. One “a” gene from mother (whose genotype for hair was aa) and second “a”gene from father (whose genotype was Aa)

4. False. She was having straight hair

5. Offspring of Paul and Jane

DdAa (4), Ddaa (4), ddAa(4) and ddaa (4)

4 out of 16 offspring will have curly hair and dimples = 0.25

6. ddaa, 4/16 = 0.25

7. Ddaa , 4/16 = 0.25

8. Ddaa, DdAa, 8/16 = 0.5

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3 years ago

In this lab, the three flocks of birds changed in numbers between generation 1 and generation 3. Why? Check all reasons. The amo

Vlad [161]

Answer:

<u>Option-</u> "If a flock’s beak type made it easier to pick up the available food, the flock grew."

Explanation:

We can simplify the whole answer by having argument about the structure or alignment of the birds in a given way which provides more food sources or options for the 1st generation and then the third generation can be found in a more scattered form inside the herd, as there are no more food requirement as much was before.

6 0

3 years ago

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