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kodGreya [7K]
2 years ago
7

What is an equation of the line that passes through the point (4,-3)(4,−3) and is perpendicular to the line 4x+y=34x+y=3?

Mathematics
1 answer:
zlopas [31]2 years ago
8 0

Step-by-step explanation:

Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

4x+ y= 3

y= -4x + 3

slope = -4

the new slope = 1/4

the equation formula y= mx+b

m = new slope

y = (x/4) + b

From the point given (4,-3)

y = -3. x = 4

-3 = 1 + b

b = -4

the equation =

y =  \frac{1}{4} x - 4

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prohojiy [21]

Answer:

y=2/3x+4.3

Step-by-step explanation:

y=mx+c

(5-3)/(1--2)

2/3= gradient

y=2/3x +c

5=2/3(1)+c

-2/3

4.3=c

6 0
2 years ago
4. Two families went camping. The Becker family was 4 miles west of the campsite lake. The Dunn family
tresset_1 [31]

They were 1 mile away from each other.

4-3=1 mile

8 0
3 years ago
The amount $4.50 is 6% of what price
Vladimir79 [104]

Answer:

0.75

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4.50 is 6% of 75% then 0.75 is 75% in decimal form, so 0.75 is 6% of 4.50

Hope I helped :)

3 0
3 years ago
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Isabella solved the following equation: 4x − 2x + 8 = 6(x + 4) Step Work Justification 1 4x − 2x + 8 = 6x + 24 Distributive Prop
AnnZ [28]

Answer:

step 3 has incorrect justification.

Step-by-step explanation:

because it was combine like terms but 8 is still in left hand side. So,combine like terms 3 has incorrect justification.

7 0
3 years ago
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Can you guys help we with this question. ​​​​​​
satela [25.4K]

Answer:

40

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2

= (4x^2-1/4(x)^2)^5

now

x =4x^2. ,a = 1/4(x)^2 ,n =5

we have

general term = Cr *x^r *a^(n-r)

= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)

= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)

= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)

= Cr * 4(2r-n) *x(4r-2n)

now for x^2

4r-2n = 2

4r -10=2

4r =12

r = 3

now for coeff

C(5,3) * 4^(2*3-5)

5!/(3!*(5-3)!) * 4

5*4/(2*1)*4

40

4 0
2 years ago
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