Question

What is an equation of the line that passes through the point (4,-3)(4,−3) and is perpendicular to the line 4x+y=34x+y=3?

Answer 1

Step-by-step explanation:

Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

4x+ y= 3

y= -4x + 3

slope = -4

the new slope = 1/4

the equation formula y= mx+b

m = new slope

y = (x/4) + b

From the point given (4,-3)

y = -3. x = 4

-3 = 1 + b

b = -4

the equation =

$y = \frac{1}{4} x - 4$