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Evgesh-ka [11]
3 years ago
10

Percentage are dogs?

Mathematics
1 answer:
Debora [2.8K]3 years ago
7 0

20% of 200 is 40 so 40 students cannot yet drive.

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I'm giving out brainliest, to the person who is right!
Brilliant_brown [7]

Answer:

the second bag

Step-by-step explanation:

to find it u have to think of it as fractions. 3/20 has to equal ?/500  so divide 500 by 20 and you get 25. then multiply the 3 by 25 which equals 75. so it would be 75/500 which is less than 170/500  

8 0
3 years ago
2- 10+ x = 6 -8 + 12<br> Please answer ASAP :)
Arisa [49]

Answer: X=18

Step by Step:

2−10+x=6−8+12

Step 1: Simplify both sides of the equation.

2−10+x=6−8+12

2+−10+x=6+−8+12

(x)+(2+−10)=(6+−8+12)(Combine Like Terms)

x+−8=10

x−8=10

Step 2: Add 8 to both sides.

x−8+8=10+8

x=18

5 0
3 years ago
Read 2 more answers
I need help on 5 and 6 please HELP ME
morpeh [17]
480 breaths in 2 minutes
8 0
3 years ago
A spinner of 10 divisions, numbered from 1 to 10, is spun and two coins are tossed. What is the probability to land on a prime n
pogonyaev

Answer:

1/10

Step-by-step explanation:

There are 4 prime numbers from 1 to 10 (2,3,5,7). This makes the probability of getting a prime number as 4/10 = 2/5.

The probability of getting one tail is 1/2, making the proability of getting 2 to be (1/2)^2 = 1/4.

Multiply both probabilities together, and you get 2/5 * 1/4 = 1/10

6 0
4 years ago
Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y
professor190 [17]

Answer:

Required total charge is 256\pi coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

x^2=y^2\leq 16 so that the charge density at (x,y) is,

\rho (x,y)=2x+2y+2x^2+2y^2

To find total charge on the disk let Q be the total charge and x=r\cos\theta,y=r\sin\theta so that,

Q={\int\int}_Q\rho(x,y) dA                where A is the surface of disk.

=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA

=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta

=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta

=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta

=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta

=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi

=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi

=256\pi

Hence total charge is 256\pi coulombs per square meter.

3 0
3 years ago
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