$ut = \sqrt{ {6}^{2} + {5}^{2} } \\ \sqrt{36 + 25} \\ \sqrt{61 } \\ using \: cosine \: rule \\ cos \: u = \frac{ {5}^{2} + 61 - 36 }{2 \times 5 \times \sqrt{61} } \\ \\ = \frac{25 + 61 - 36}{78} \\ \\ = \frac{50}{78 } \\ \cos \: u = 0.64 \\ m \:u = 50.2$

4 0

3 years ago

How do you do this? I need to know the measurements of all the angles that are labeled

nekit [7.7K]

Im assuming that's a regular octagon. The sum of the angles in an octagon is 1080, so that means each individual angle is 135.

m<1 = 135.

Not completely sure how to get the others. Is there any information on the triangles or the octagon that isn't included in the picture? Lmk if you do and I can solve the rest

4 0

4 years ago

Help me find Angle B

DENIUS [597]

Answer:

55 degrees

Step-by-step explanation:

180-95-30=55

6 0

3 years ago