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algol [13]
3 years ago
9

A van travels at a constant speed of x km/hr over a distance of 45km/hr. If the van increases its speed by 4km/h, it will be abl

e to travel a distance of 48km in the same amount of time. Calculate x.

Mathematics
1 answer:
harkovskaia [24]3 years ago
8 0
Speed = Distance/Time. Let speed be V, distance D and time T

a)Given: D₁ =45km, V₁=x km/h 
V₁=D₁/T
V₁=45/T OR T= 45/V₁

b) Given : D₂ =48 km and V₂ = V₁ + 4 km/h
V₂ = 48/T, but V₂ = V₁+4, then:

V₁+4 = 48/T OR  T=48/(V₁+4). Since Time is same, then we can write:
45/V₁ =48/(V₁+4), solve for V₁:
45V₁ + 180 = 48V₁

3V₁ =180 and V₁ = x = 60 km/h
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Answer:

113.7-2.154\frac{9.1}{\sqrt{29}}=110.06    

113.7+2.154\frac{9.1}{\sqrt{29}}=117.34    

And the 96% confidence is given by (110.06; 117.34)

Step-by-step explanation:

Information given

\bar X=113.7 represent the sample mean

\mu population mean (variable of interest)

s=9.1 represent the sample standard deviation

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Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=29-1=28

The Confidence is 0.96 or 96%, the significance is \alpha=0.04 and \alpha/2 =0.02, and the critical value would be t_{\alpha/2}=2.154

Replacing the info we got:

113.7-2.154\frac{9.1}{\sqrt{29}}=110.06    

113.7+2.154\frac{9.1}{\sqrt{29}}=117.34    

And the 96% confidence is given by (110.06; 117.34)

5 0
3 years ago
Can someone explain to me how to do this? I just don't get it.
Maksim231197 [3]

Answer:

x=130

Step-by-step explanation:

triangle=180

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line=180

180-50=130

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