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Margarita [4]
3 years ago
10

A recipe calls for 5/4cups of flour for every 4 cups of water. How many cups of flour are needed for 28 cups of water?

Mathematics
1 answer:
podryga [215]3 years ago
6 0

Answer:

35/4

Step-by-step explanation:

28/4=7

7×5/4

=8.75

=35/4

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Here is the question here please answer
earnstyle [38]

Daaaaaaaaaammmmm that’s hard

4 0
3 years ago
cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0
Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder=2\pi rh

Area of circular base=Area of circular top=\pi r^2

Total cost,C(r)=0.02\times 2\pi rh+2\pi r^2\times 0.07

Volume of cylinder,V=\pi r^2 h

200=\pi r^2 h

h=\frac{200}{\pi r^2}

Substitute the value of h

C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07

C(r)=\frac{8}{r}+0.14\pi r^2

Differentiate w.r.t r

C'(r)=-\frac{8}{r^2}+0.28\pi r

C'(r)=0

-\frac{8}{r^2}+0.28\pi r=0

0.28\pi r=\frac{8}{r^2}

r^3=\frac{8}{0.28\pi}=9.095

r=(9.095)^{\frac{1}{3}}=2.09

Again, differentiate w.r.t r

C''(r)=\frac{16}{r^3}+0.28\pi

Substitute the value of r

C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0

Therefore,the product cost is minimum at r=2.09

h=\frac{200}{\pi (2.09)^2}=14.57

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0
3 years ago
drew makes $8 a week on allowance and pends $3. write an expression to show how much he has at the end of the week. Use parenthe
postnew [5]
X is how much he makes in a week. 7(8-3)=x
6 0
3 years ago
Describe the error in the work shown. 62​ + 3 + 5 x 2 ​ ​ 36 + 8 x 2 ​36 + 16 52
makkiz [27]

Answer:

There is an error in the application of the DMAS rule, The answer as per the DMAS rule is 75.

Step-by-step explanation:

There is an error in the implication of the DMAS rule of Mathematics.

DMAS rule determines the arrangement of mathematical functions to be performed in an expression where multiple functions are present.

The DMAS Rules describes the following arrangement of the mathematical functions.

1st Division

2nd Multiplication

3rd Addition

4th Subtraction

Applying the above rule the solution is as follow

62​ + 3 + 5 x 2 ​ ​

First, we need to solve the Multiplication because there is no division

62​ + 3 + 10

Now perform the addition function

65 + 10

75

6 0
2 years ago
A. -5<br> B. 5<br> C. -2<br> D. 3
Anna71 [15]

Answer:

\textsf {C. -2}

Step-by-step explanation:

\textsf{In the equation y = mx + b, m is the slope and} \\\textsf{b is the value of the y-intercept.}

\textsf {The line has a y-intercept at (0, -2), hence b = -2.}

5 0
2 years ago
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