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balu736 [363]
3 years ago
7

Use the regular hexagon PORSTU to answer the question.

Mathematics
2 answers:
gavmur [86]3 years ago
6 0

Answer:

Step-by-step explanation:

A reflection across UT

hope this helps you!

garik1379 [7]3 years ago
5 0

Answer:

A reflections across UT

Step-by-step explanation:

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HELP ME PLS
sammy [17]

Answer:

answer is A

Step-by-step explanation:

7 0
3 years ago
What is slope when talking about math
dolphi86 [110]
When graphing, its how much you rise and run
thats the formula when u have a graph and the question is asking for the slope.
you chose a point, and go down or up however many times it goes to the next point, and you run to the left however many times it gets you to get to that point.
if the line goes downward the slope is therefore negative, and if the line goes upward, the slope is therefore, positive.
m in math is meant to be slope, so m= \frac{rise}{run}
7 0
3 years ago
Read 2 more answers
Are the ratios 2:3 and 1:2 equivalent??
Mila [183]

Answer:

No coz 2:3 is 2+3=5

1:2 is 1+2=3 so they are not equivalent.

6 0
3 years ago
Start at (12, 3). Move 2 units right and 7 units up. Where do you end up?
Korolek [52]

Answer: (10, 10)

Step-by-step explanation: well if you say start at (12, 3) move 7 units up then 3 units right then it would make it easier to figure it out cus as you can see start at 3 and go up 7 it would stop at 10 then if you go over 2 from 12 it would stop at 10

6 0
3 years ago
Solve the equation using the quadratic formula. Enter each solution in simplest form.
sergeinik [125]

For this case we have the following quadratic equation:

x ^ 2-4x + 23 = 0

The solutions will be given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Where:

a = 1\\b = -4\\c = 23

Substituting the values we have:

x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (23)}} {2 (1)}\\x = \frac {4 \pm \sqrt {16-92}} {2}\\x = \frac {4 \pm \sqrt {-76}} {2}\\x = \frac {4 \pm \sqrt {76i ^ 2}} {2}\\x = \frac {4 \pmi \sqrt {76}} {2}\\x = \frac {4 \pmi \sqrt {2 ^ 2 * 19}} {2}\\x = \frac {4 \pm2i \sqrt {19}} {2}\\x = 2 \pm i\sqrt {19}

We have two roots:

x_ {1} = 2-i \sqrt {19}\\x_ {2} = 2 + i \sqrt {19}

ANswer:

x_ {1} = 2-i\sqrt {19}\\x_ {2} = 2 + i\sqrt {19}

6 0
4 years ago
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