Answer:
1/36
Step-by-step explanation:
When the coefficient is 1, the function has zeros at -3 and -5, one horizontal unit from the vertex. You want to move the zero to (2, 0), which is 6 units from the vertex. To achieve a horizontal stretch by a factor of 6, the value of x in the function must be replaced by x/6. That would make the coefficient of x^2 be (1/6)^2 = 1/36.
The coefficient of the squared term is 1/36.
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One method is to plot the points P(3,6) and Q(7,3) on the same xy grid. Plot a third point R at (3,3). See the diagram below.
A right triangle forms in which we can find the legs PR = 3 and RQ = 4. The hypotenuse is found through the pythagorean theorem.
a^2+b^2=c^2
3^2+4^2 = c^2
9+16 = c^2
c^2 = 25
c = sqrt(25)
c = 5
This is the length of PQ
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Or you can use the distance formula which is effectively using the pythagorean theorem just in a slightly different format (though it may not be obvious).
