With 5 elements in A={20,1,6,10,11}, there are 2^5=32 possible subsets, including
the null set, and A itself.
Any subset that is identical to A is NOT a proper subset.
Therefore there are 31 proper subsets, plus the subset {20,1,6,10,11}.
The subsets are:
null set {} (has no elements) ........total 1
{20},{1},{6},{10},{11}.......................total 5
{20,1},{20,6}...{10,11}.....................total 10
{20,1,6},{20,1,10},...{6,10,11}.........total 10
{20,1,6,10}...{1,6,10,11}.................total 5
{20,1,6,10,11}.................................total 1
Altogether 32 subsets.
Answer: x = - 16
y = - 11
Step-by-step explanation:
The given system of linear equations is expressed as
2x - 3y = 1- - - - - - - - - - - - -1
x - 2y = 6 - - - - - - - - - - - -2
We would eliminate x by multiplying equation 1 by 1 and equation 2 by 2. It becomes
2x - 3y = 1- - - - - - - - - - -3
2x - 4y = 12- - - - - - - - - - - -4
Subtracting equation 4 from equation 3, it becomes
y = - 11
Substituting y = - 11 into equation 2, it becomes
x - 2 × - 11 = 6
x + 22 = 6
Subtracting 22 from the left hand side and the right hand side of the equation, it becomes
x + 22 - 22 = 6 - 22
x = - 16
Step-by-step explanation:
In A,
length=3units
width=2 units
area=length×width
area=3×2 sq.units
area=6 sq.units
In B,
length=1unit
width=4units
area=length × width
area=1unit × 4units
area= 4 sq.units
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Answer:
the first one is 57
the second one is 60
3rd one is 13
4th one is 9
Step-by-step explanation:
hope this helps :) have a nice day !!
**please let me know if this was wrong**
