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prisoha [69]
4 years ago
11

A reaction produces 0.829 moles of H2O. How many molecules are produced?

Chemistry
1 answer:
mr_godi [17]4 years ago
8 0
You should get 5.05 x 10^23 moles.
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A weather balloon has a volume of 52.5 liters at a temperature of 295 K. The balloon is released and rises to an altitude where
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So you have a balloon rising through the atmosphere. use the formula p1/v1=p2/v2 and add the variables into the equation, leaving 295/52.5=252/x. multiply 252 by 52.5 and divide that number by 295.
52.5*252=13230. divide by 295 =44.9 L
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What is 188.5°F in Celsius?
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That would be 86.944 Celsius

Explanation:

(188.5°F − 32) × 5/9 = 86.944°C

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Which issue associated with nuclear power is the biggest source of debate?​
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Which of these sources is most likely to be credible when it comes to information on the advantages and disadvantages of using p
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Determine the [ OH − ] , pH, and pOH of a solution with a [ H + ] of 8.2 × 10 − 10 M at 25 °C. [ OH − ] = 1.22 ×10 −5 M pH = 9.0
nika2105 [10]

Answer:

See explanation below

Explanation:

At the beggining of the  exercise, you already giving the solution for the 1st two problems, so I just going to answer the remaining question which are:

<em>"Determine the [ H + ] , [ OH − ] , and pOH of a solution with a pH of 7.20 at 25 °C. [ H + ] = M [ OH − ] = M pOH = 6.8 Determine the [ H + ] , [ OH − ] , and pH of a solution with a pOH of 6.43 at 25 °C."</em>

Now, to get every data in the problem, we need to write the expressions for every part, which are the following:

pH = -log[H⁺]   (1)

pH = 14 - pOH  (2)

[H⁺] = 10^(-pH)  (3)

[H⁺] = Kw / [OH⁻]   (4)

pOH = -log[OH⁻]  (5)

pOH = 14 - pH  (6)

[OH⁻] = 10^(-pOH)   (7)

[OH⁻] = Kw / [H⁺]  (8)

Now, according to the given data, we will use any of these eight expressions.

a) "<u><em>Determine the [ H + ] , [ OH − ] , and pOH of a solution with a pH of 7.20"</em></u>

We have pH, so in this case, we will use expression (3), (6) and (8):

[H⁺] = 10^(-7.20)

[H⁺] = 6.31x10⁻⁹ M

pOH = 14 - 7.2

pOH = 6.8

[OH⁻] = 1x10⁻¹⁴ / 6.31x10⁻⁹

[OH⁻] = 1.58x10⁻⁴ M

b) <u>"</u><u><em>The [ H + ] , [ OH − ] , and pH of a solution with a pOH of 6.43 "</em></u>

In this case, we can use expressions (2), (4) and (7). Using those expressions we have:

pH = 14 - 6.43

pH = 7.57

[H⁺] = 10^(-7.57)

[H⁺] = 2.69x10⁻⁸ M

[OH⁻] = 1x10⁻¹⁴ / 2.69x10⁻⁸

[OH⁻] = 3.72x10⁻⁷ M

4 0
4 years ago
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