There are four quantum numbers for an orbital, namely, principal quantum number n, azimuthal quantum number l, magnetic quantum number 
and spin quantum number s. No two orbitals can have same value for all the four quantum numbers.
Principal quantum number tells about the position of orbital that is shell number, azimuthal quantum number describes the shape of orbital, for s, p, d, f,... orbitals, the value is 0, 1, 2, 3,... so on. The value of magnetic quantum number varies from -l to +l (including zero), it defines the sub shell of electron. Spin of the electron defines its movement that is clockwise or anticlockwise thus, there are only two possible values for spin quantum number: +1/2 or -1/2.
For 2p orbital, principal quantum number n is 2 (denotes the shell) and azimuthal quantum number for p orbital is 1. Thus, different values for magnetic quantum number will be -l to l that is -1, 0,1.
Therefore, for 2p subshell there are 3 different values.
Nickel metal will react spontaneously with the aqueous lead solution [Pb2+(aq)].
Oxidation is a chemical reaction involving the loss of electrons. In the reactivity series of metals, chromium, barium, and lithium are more reactive or more easily oxidized than nickel.
In the given problem, because nickel is in its elemental (solid metal) form, for it to react with the solution, it will have to be converted into its cationic form (which is positively-charged) by losing electrons. However, if the solution that nickel is reacted with is more easily oxidized compared to nickel, then the reaction will not be spontaneous because nickel is stable in this case.
On the other hand, if nickel is immersed in a solution of a metal which is more stable than it is, such as lead, nickel will be oxidized and lose its electrons to the more stable metal. The more stable metal in solution will accept the lost electrons of nickel and form a solid deposit, while nickel will be in its ionic form in solution.
Below is a reaction between nickel metal and aqueous lead nitrate solution.
Answer:
Kp = 41.53
Kc = 1.01
Explanation:
To calculate the equilibrium constant in terms of pressure, what we simply do is to use the equilibrium pressure raised to the power of the number of moles. What we are saying in essence is this:
Kp = [NOCl]^2/[NO]^2[Cl]
Kp= [0.25]^2/[0.174][0.093]^2 = 41.53
Kp = Kc (RT)^Dn
Hence, Kc = Kp/[RT]^(delta n )^-1
n = sum of the number of moles of products minus the sum of the number of moles of reactants= 2-3 = -1 in this case
Kc = 41.53/(0.0821 * 500)^1
Kc = 1.01
