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3 years ago

What would you use if you needed to determine the density of an object?

1 answer:

8 0

What would you use if you needed to determine the density of an object?

Balance and Graduate Cylinder

Hope This Helps! \(★ω★)/

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PLease help!!! Im in the process of taking my final!!!!! HELPPPPP

Katarina [22]

Answer:

The answer to your question is Aluminum

Explanation:

Number of clues

1.- If this element has 3 rings in its Bohr model, we are looking for and element located in the third period of the periodic table.

For example Sodium, Magnesium, Aluminum, Silicate, Phosphorus, Sulfur, Chlorine and, Argon.

2.- It makes three bonds to become stable, then we are looking for and element located in the third group like

Boron, Aluminum, Gallium, Indium, etc

Conclusion

The element that has both characteristics is Aluminum

8 0

3 years ago

Which statement describes the effect of sorting and recombining genes in sexual reproduction?

Setler79 [48]

The fourth option I think

7 0

3 years ago

Adding a neutron to an atom changes what property of the atom?

GrogVix [38]

C, The atomic mass. This could also cause certain elements (i.e. Uranium, Plutonium) to radioactively decay in process called nuclear fission.

3 0

3 years ago

Read 2 more answers

Emperical formula of carbon dioxide

Stells [14]

CO2 is the emperical formula of carbon dioxide

6 0

3 years ago

Read 2 more answers

Alveoli are tiny sacs of air in the lungs. Their average diameter is 4.50 × 10−5 m. Calculate the uncertainty in the velocity of

Arisa [49]

Answer: The uncertainty in the velocity of oxygen molecule is $4.424\times 10^{-5}m/s$

Explanation:

The diameter of the molecule will be equal to the uncertainty in position.

The equation representing Heisenberg's uncertainty principle follows:

$\Delta x.\Delta p=\frac{h}{2\pi}$

where,

$\Delta x$ = uncertainty in position = d = $4.50\times 10^{-5}m$

$\Delta p$ = uncertainty in momentum = $m\Delta v$

m = mass of oxygen molecule = $5.30\times 10^{-26}kg$

h = Planck's constant = $6.627\times 10^{-34}kgm^2/s^2$

Putting values in above equation, we get:

$4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg}=4.424\times 10^{-5}m/s$

Hence, the uncertainty in the velocity of oxygen molecule is $4.424\times 10^{-5}m/s$

8 0

3 years ago