F((h(x)) = 2(x^2 + 1) - 1 = 2x^2 + 1 (replace the x in f(x) by h(x))
g ( f(x)) = 3(2x - 1) = 6x - 3 (replace the x in g(x) by f(x))
Answer:
14
Step-by-step explanation:
Its like a clock, except directly away from the six is not twelve, it's 13. That means the clock would have to have added two numbers for there to be a whole number facing the six.
900$ loss
X/150=.05/1
x= 142.5
120(142.5)=17100
120(150)= 18000
18000-17100= 900
16 times but the answer is 16.3(repeating)
