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kakasveta [241]
2 years ago
10

Answer Questions and show all of your work.

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
6 0

Answer:

X= 35

Z=90

Step-by-step explanation:

sorry I don’t know how else to help

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John walked 8 min 12 sec Kim walked 7 min 31 sec how many more sec does Kim walk
Masteriza [31]

Answer:

41 seconds

Step-by-step explanation:

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3 years ago
Solve the quadratic equation by using the quadratic formula. if the solution are not real, enter N/A 3x^2-7x+1=0
Vsevolod [243]

Answer:

\displaystyle x=\frac{7\pm\sqrt{37}}{6}

Step-by-step explanation:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\frac{-(-7)\pm\sqrt{(-7)^2-4(3)(1)}}{2(3)}\\\\x=\frac{7\pm\sqrt{49-12}}{6}\\ \\x=\frac{7\pm\sqrt{37}}{6}

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2 years ago
Simplify (8x^2 − 1 + 2x^3) − (7x^3 − 3x^2 + 1).
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8x^2-1+2x^3-7x^3+3x^2-1

-5x^3+11x^2-2


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3 years ago
True or False.<br> 43 = 62
strojnjashka [21]
False...............
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3 years ago
Assume that random guesses are made for seven multiple choice questions on an SAT​ test, so that there are nequals7 ​trials, eac
Ket [755]

Answer:

P(X < 4)=0.1335+0.3115+0.3115+0.1730=0.9295

Step-by-step explanation:

Question assumed: Find the probability that the number x of correct answers is fewer than 4.

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=7, p=0.25)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X < 4)=P(X=0)+P(X=1)+P(X=2)+P(X=3)

P(X=0)=(7C0)(0.25)^0 (1-0.25)^{7-0}=0.1335

P(X=1)=(7C1)(0.25)^1 (1-0.25)^{7-1}=0.3115

P(X=2)=(7C2)(0.25)^2 (1-0.25)^{7-2}=0.3115

P(X=3)=(7C3)(0.25)^3 (1-0.25)^{7-3}=0.1730

P(X < 4)=0.1335+0.3115+0.3115+0.1730=0.9295

3 0
4 years ago
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