recall d = rt, distance = rate * time.
let's say airplane A is going at a rate of "r", therefore airplane B is moving faster, at a rate of "r + 80".
now, after 3 hours, both planes have been travelling for 3 hours each, and say if A has covered "d" miles, then B has covered the slack of 2490 - d.
![\bf \leftarrow \underset{A}{\stackrel{r}{\rule[0.22em]{8em}{0.25pt}}}dallas\underset{B}{\stackrel{r+80}{\rule[0.22em]{18em}{0.25pt}}}\to \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ plane~A&d&r&3\\ plane~B&2490-d&r+80&3 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cleftarrow%20%5Cunderset%7BA%7D%7B%5Cstackrel%7Br%7D%7B%5Crule%5B0.22em%5D%7B8em%7D%7B0.25pt%7D%7D%7Ddallas%5Cunderset%7BB%7D%7B%5Cstackrel%7Br%2B80%7D%7B%5Crule%5B0.22em%5D%7B18em%7D%7B0.25pt%7D%7D%7D%5Cto%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Blcccl%7D%20%26%5Cstackrel%7Bmiles%7D%7Bdistance%7D%26%5Cstackrel%7Bmph%7D%7Brate%7D%26%5Cstackrel%7Bhours%7D%7Btime%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20plane~A%26d%26r%263%5C%5C%20plane~B%262490-d%26r%2B80%263%20%5Cend%7Barray%7D)
Answer:
the answer is A
Step-by-step explanation:
y=-7/4x-3
Answer:
small waist pretty face with a big bang
Step-by-step explanation:
Answer:
f(7)=13
g(-9)=86
Step-by-step explanation:
f(7)=2*7-1=14-1=13
g(-9)=(-9)^2+5=81+5=86
If you do 405.54-340.00=65.54. So the answer would be D, $65.54 over budget. Hope you have an amazing day! let me know if you need help with anything else! :D
