Answer:
82.79MPa
Step-by-step explanation:
Minimum yield strength for AISI 1040 cold drawn steel as obtained from literature, Sᵧ = 490 MPa
Given, outer radius, r₀ = 25mm = 0.025m, thickness = 6mm = 0.006m, internal radius, rᵢ = 19mm = 0.019m,
Largest allowable stress = 0.8(-490) = -392 MPa (minus sign because of compressive nature of the stress)
The tangential stress, σₜ = - ((r₀²p₀)/(r₀² - rᵢ²))(1 + (rᵢ²/r²))
But the maximum tangential stress will occur on the internal diameter of the tube, where r = rᵢ
σₜₘₐₓ = -2(r₀²p₀)/(r₀² - rᵢ²)
p₀ = - σₜₘₐₓ(r₀² - rᵢ²)/2(r₀²) = -392(0.025² - 0.019²)/2(0.025²) = 82.79 MPa.
Hope this helps!!
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ANSWER:
Answer: the answer is 3.6 mph
Step-by-step explanation: to find the average speed you need to divide your total distance by total time. Im this case you need to divide 12 by to find the average speed you need to divide your total distance by total time. Im this case you need to divide 12 by 3.25
Using pythagorean's theorem
a^2+b^2=c^2
a being 3
b being 4
we'll get
9+16=25
where 5 is the hypotenuse and also c.
c^2 = 5^2
We need to make h alone.
Add 7 to both sides to remove -7 from the right, and multiply both sides by -1 to make h positive. Doesn't matter which you do first.
Result:
6=h
h=6
