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3 years ago

Which of the following correctly describes the inflammatory reaction?

Physics

1 answer:

jok3333 [9.3K]3 years ago

3 0

Answer:

I think D.

Injured cells stimulate pain, swelling, redness, and heat- which initiates bradykinin-which stimulates the release of histamine- which increases neutrophils and macrophages- leads to phagocytosis of foreign invaders.

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The distance between your school and house is 80 m. In going to your school starting from your

SIZIF [17.4K]

Answer:

a) 2/3 m/s

b) 0.0143 m/s

c) 0.00 m/s

Explanation:

a) 80 m / (2(60) s = 2/3 m/s

b) 2(80) / (3(3600) + (2 + 4)(60)) = 160 / 11,160 = 0.0143 m/s

c) start and end at your house. no displacement, no velocity.

8 0

3 years ago

. A driver travels 4.25 km. in two minutes. If the driver’s initial velocity is 20m/s, what is the acceleration?

Novosadov [1.4K]

Answer:

32.9166667 m / s^2

Explanation:

s = 4.25km (1000m / 1km)

= 4250m

u = 20m/s

delta T = 20min (60sec / 1min)

= 1200s

Use formula s = ut + (1/2)at^2

4250m = 20m/s * 1200s + (1/2)a*1200s^2

Rearrange it to find a

a = (s-ut) / (1/2 * t^2)

a = (4250m - 20m/s*1200s) / (1/2 * 1200s^2)

a = -32.9166667 m / s^2

4 0

3 years ago

What is the kinetic energy of a 30 kg falling object when the object reaches a velocity of 20 m/s?

Oksi-84 [34.3K]

Ek = 1/2mv^2 Ek = 1/2 * 30kg * 20^2 m/s Ek = 6000J Hope this Helps!

6 0

3 years ago

Help with this question.....

mariarad [96]

Answer:

$g_{moon}=1.67 [m/s^{2} ]$

Explanation:

The weight of some mass is defined as the product of mass by gravitational acceleration. In this way using the following formula we can find the weight.

$w =m*g\\$

where:

w = weight [N]

m = mass = 0.06 [kg]

g = gravity acceleration = 10 [N/kg]

Therefore:

$w=0.06*10\\w=0.6[N]$

By Hooke's law we know that the force in a spring can be calculated by means of the following expression.

$F=W\\F = k*x$

where:

k = spring constant [N/m]

x = deformed distance = 6 [cm] = 0.06 [m]

We can find the spring constant.

$k= F/x\\k=0.6/0.06\\k=10 [N/m]$

Since we use the same spring on the moon and the same mass, the constant of the spring does not change, the same goes for the mass.

$F_{moon}=k*0.01\\F = 10*0.01\\F=0.1[N]$

Since this force is equal to the weight, we can now determine the gravitational acceleration.

$F=m*g_{moon}\\g=F/m\\g = 0.1/0.06\\g_{moon} = 1.67[m/s^{2} ]$

6 0

3 years ago

In Pensacola in June, high tide was at noon. The water level at high tide was 12 feet and 2 feet at low tide. Assuming the next

Sveta_85 [38]

<span>To answer this question, the equation that we will be using is:
y = A cos bx + c
where A = amplitude, b = 2 pi/Period, Period = 12 hrs, c = midline,
x = t and y = f(t)

A = 1/2 (Xmax - Xmin)
12 - 2 / 2 = 10/2 = 5
b = 2 pi / 12 = pi/6
c = 1/2 (Xmax + Xmin)
12+2/2 = 7
answer: f(t) = 5 cos pi/6 t + 7 </span>

8 0

4 years ago