Answer:
454,320 joules
Explanation:
The work done on an object is equal to its change in kinetic energy: Change in KE = F × d.
Plug the values for F and d into the formula and solve:
Change in KE = 2,524 × 180
= 454,320 joules
The roller coaster gains 454,320 joules of energy from the work done on it by the chain.
Hey
So first we need to know what the direction of the force is, using your right hand rule point your right hand in the direction of the velocity. You're saying its the z direction, not telling me whether it's into the page or out? Since its a positive z im assuming its coming out. The magnetic field is pushing it upwards, so the force is going in the negative x direction.
The force of a magnetic field is
F = Qv X B
What's weird is that you don't need mass in this equation. Actually you don't even need the formula, its telling you that they're all going in perpendicar directions. the answer is 90 degrees.
Now if you want to know the F just multiply the charge, velocity and magnetic field .
F = GVB
F = 6.048 E -15
Answer : 90 degrees, sin(90) = 1
Answer:
1.52m/s
Explanation:
Using the law of conservation of momentum
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses
u1 and u2 are the initial velocities
v is the final velocity
Substitute the given values into the formula
0.013(270)+2(130) = (270+130)v
3.51+260 = 400v
263.51 = 400v
v = 400/263.51
v = 1.52m/s
Hence the velocity after the bullet emerges is 1.52m/s
Opposite charges attract
Like charges repel
Answer:
y₁ = 37.2 m, y₂ = 22,6 m
Explanation:
For this exercise we can use the kinematic equations
For the globe, with index 1
y₁ = y₀ + v₁ t
For the shot with index 2
y₂ = 0 + v₂ t - ½ g t²
At the point where the position of the two bodies meet is the same
y₁ = y₂
y₀ + v₁ t = v₂ t - ½ g t²
14 + 8.40t = 27.0 t - ½ 9.8 t²
4.9 t² - 18.6 t + 14 = 0
t² - 3,796 t + 2,857 = 0
Let's look for time by solving the second degree equation
t = [3,796 ±√(3,796 2 - 4 2,857)] / 2
t = [3,796 ± 1,727] / 2
t₁ = 2.7615 s
t₂ = 1.03 s
Now we can calculate the distance for each time
y₁ = v₂ t₁ - ½ g t₁²
y₁ = 27 2.7615 - ½ 9.8 2.7615²
y₁ = 37.2 m
y₂ = v₂ t₂ - ½ g t₂²
y₂ = 27 1.03 - ½ 9.8 1.03²
y₂ = 22,612 m