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sukhopar [10]
3 years ago
7

What is the kinetic energy of a 30 kg falling object when the object reaches a velocity of 20 m/s?

Physics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0
Ek = 1/2mv^2 Ek = 1/2 * 30kg * 20^2 m/s Ek = 6000J Hope this Helps!
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Some of the energy the car gained as it was pulled was lost because of heat from friction. The rest of the energy was transforme
Lisa [10]

Answer:

454,320 joules

Explanation:

The work done on an object is equal to its change in kinetic energy: Change in KE = F × d.

Plug the values for F and d into the formula and solve:

Change in KE = 2,524 × 180

= 454,320 joules

The roller coaster gains 454,320 joules of energy from the work done on it by the chain.

7 0
3 years ago
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A proton has a charge of 1.6 × 10-19 C and a mass of 1.67 × 10-27 kg. A proton moves with velocity 1.8 × 105 m/s in the z-direct
lord [1]

Hey

So first we need to know what the direction of the force is, using your right hand rule point your right hand in the direction of the velocity. You're saying its the z direction, not telling me whether it's into the page or out? Since its a positive z im assuming its coming out. The magnetic field is pushing it upwards, so the force is going in the negative x direction.

The force of a magnetic field is

F = Qv X B

What's weird is that you don't need mass in this equation. Actually you don't even need the formula, its telling you that they're all going in perpendicar directions. the answer is 90 degrees.

Now if you want to know the F just multiply the charge, velocity and magnetic field .

F = GVB

F = 6.048 E -15

Answer : 90 degrees, sin(90) = 1

6 0
3 years ago
a 13-gram bullet, moving at 270 m/s, penetrates a 2 kg block of wood and emerges at a speed of 130 m/s. if teh block sits one a
saveliy_v [14]

Answer:

1.52m/s

Explanation:

Using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the final velocity

Substitute the given values into the formula

0.013(270)+2(130) = (270+130)v

3.51+260 = 400v

263.51 = 400v

v = 400/263.51

v = 1.52m/s

Hence the velocity after the bullet emerges is 1.52m/s

6 0
3 years ago
Opposite chargers and like charges
cluponka [151]
Opposite charges attract
Like charges repel
7 0
3 years ago
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Review Interactive LearningWare 2.2 as an aid in solving this problem. A hot air balloon is ascending straight up at a constant
Ksivusya [100]

Answer:

y₁ = 37.2 m,      y₂ = 22,6 m

Explanation:

For this exercise we can use the kinematic equations

For the globe, with index 1

       y₁ = y₀ + v₁ t

For the shot with index 2

       y₂ = 0 + v₂ t - ½ g t²

 At the point where the position of the two bodies meet is the same

        y₁ = y₂

        y₀ + v₁ t = v₂ t - ½ g t²

        14 + 8.40t = 27.0 t - ½ 9.8 t²

        4.9 t² - 18.6 t + 14 = 0

        t² - 3,796 t + 2,857 = 0

Let's look for time by solving the second degree equation

         t = [3,796 ±√(3,796 2 - 4 2,857)] / 2

         t = [3,796 ± 1,727] / 2

         

         t₁ = 2.7615 s

         t₂ = 1.03 s

Now we can calculate the distance for each time

         y₁ = v₂ t₁ - ½ g t₁²

        y₁ = 27 2.7615 - ½ 9.8 2.7615²

        y₁ = 37.2 m

       

        y₂ = v₂ t₂ - ½ g t₂²

        y₂ = 27 1.03 - ½ 9.8 1.03²

        y₂ = 22,612 m

3 0
3 years ago
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