3 years ago

Uhhh I need help again today

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

8 0

Answer:

What you need help with or is it something dealing with personal issues?

trapecia [35]3 years ago

7 0

I guess I could help, what grade?

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No extraneous solution

Step-by-step explanation:

We have the logarithmic equation given by,

$\log_{2}[\log_{2}(\sqrt{4x})]=1$

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