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exis [7]
2 years ago
8

Wind farms are a source of renewable energy found around the world. The power P (in kilowatts) generated by a wind turbine varie

s directly as the cube of the wind speed v (in meters per second). If a turbine generates 700 kW in a 12 m/s wind, how much power does it generate in a 6 m/s wind?
(The formula for P as a power function of v is P = a ⋅ v3.


A. 88 kW

B. 175 kW

C. 125 kW

D. 1050 kW
Mathematics
1 answer:
kodGreya [7K]2 years ago
4 0

Answer:

New power = 88 Kw (Approx.)

Step-by-step explanation:

Given:

P = a(v³)

Old power p = 700 Kw

Old wind speed v = 12 m/s

Find:

New power when v = 6m/s

Computation:

P = a(v³)

700 = a(12³)

a = 0.4050 m²

New power = a(v³)

New power = (0.4050)(6³)

New power = 87.48

New power = 88 Kw (Approx.)

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They will be 15 miles apart after one hour if they left the same point at the same time.

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The distance between two points in geometry can be calculated by using the Pythagoras theorem.

Mathematically, the Pythagoras theorem can be expressed as:

\mathbf{d = \sqrt{x^2 +y^2}}

where;

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\mathbf{d = \sqrt{(9)^2 +(12)^2}}

\mathbf{d = \sqrt{81+144}}

\mathbf{d = \sqrt{225}}

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2 years ago
There are 4 different math courses, 5 different science courses, and 2 different history courses. If a student must take one of
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A student can take three subjects in 40 ways.

<u>SOLUTION:</u>

Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.

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Now, number ways to take math course = 4

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So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.

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3 years ago
Consider functions
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b is the correct answer

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6 0
2 years ago
Maryland had $(62xsquared + x - 4) on mondays she spent $(11x squared - 33) on a pair of gloves how much money did she have left
Anton [14]

Answer:

$( 51x^2 + x + 29).

Step-by-step explanation:

Amount she had left = original amount - amount spent on the gloves

=  62x^2 + x - 4 - (11x^2 - 33)   (note we place the amount spent on gloves in parentheses because we have to subtract the whole amount)

Now we distribute the negative over the parentheses:

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Now simplifying like terms:

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7 0
3 years ago
Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
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Answer:

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and

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the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

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It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

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Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
3 years ago
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