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exis [7]
3 years ago
8

Wind farms are a source of renewable energy found around the world. The power P (in kilowatts) generated by a wind turbine varie

s directly as the cube of the wind speed v (in meters per second). If a turbine generates 700 kW in a 12 m/s wind, how much power does it generate in a 6 m/s wind?
(The formula for P as a power function of v is P = a ⋅ v3.


A. 88 kW

B. 175 kW

C. 125 kW

D. 1050 kW
Mathematics
1 answer:
kodGreya [7K]3 years ago
4 0

Answer:

New power = 88 Kw (Approx.)

Step-by-step explanation:

Given:

P = a(v³)

Old power p = 700 Kw

Old wind speed v = 12 m/s

Find:

New power when v = 6m/s

Computation:

P = a(v³)

700 = a(12³)

a = 0.4050 m²

New power = a(v³)

New power = (0.4050)(6³)

New power = 87.48

New power = 88 Kw (Approx.)

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mezya [45]

Answer:

Step-by-step explanation:

Let x = the number of 50-cent increases in the cost of a book rental.

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$3 + .5x = the price per book rental after the increase. That's how much money he will make. The money made is NOT the same thing as the number of rentals. Therefore, they are put into separate expressions.

The number of rentals is:

38 - 4x. This is the number of books he is currently renting minus the number of book rentals he will lose per price increase. Putting those 2 expressions together and multiplying them will give you the end result of this increase in price.

(3 + .5x)(38 - 4x) = 114 - 12x + 19x - 2x², or putting it in descending powers of x and combining like terms:

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7 0
4 years ago
Find the intersection of the lines 2x+5y=8 and 6x+y=10 in two ways by elimination and by substitution, step by step please.
Law Incorporation [45]

Answer:

The lines intersect at x = 1.5 and y = 1

Step-by-step explanation:

We need to find  the intersection of the lines 2x+5y=8 and 6x+y=10.

We need to find the values of x and y by elimination and by substitution.

a) By Elimination:

2x+5y = 8     (1)

6x + y = 10    (2)

Multiply eq(2) with 5 and subtract eq(1) from(2)

30x + 5y = 50

2x   + 5y = 8  

-      -         -

___________

28x = 42

x = 1.5

Now putting value of x in eq(2)

6x + y = 10

6(1.5) + y = 10

9 + y = 10

=> y = 10 - 9

y = 1

so, (x,y) = (1.5,1)

The lines intersect at x = 1.5 and y = 1

b) By substitution

2x+5y = 8     (1)

6x + y = 10    (2)

Finding value of y in equation 2 and substituting in eq(1)

y = 10 -6x

2x + 5(10 - 6x) = 8

2x + 50 - 30x = 8

-28x = 8-50

-28x = -42

x = -42/-28

x = 1.5

Now finding value of y by substituting value of x

6x + y = 10

6x = 10-y

x = 10 - y /6

2x + 5y = 8

2(10-y/6) + 5y = 8

10-y/3 + 5y = 8

10 -y +15y/3 = 8

10 +14y = 8*3

+14 y = 24 -10

+14 y =  14

y = 14/14

y = 1

So, (x,y) = (1.5,1)

The lines intersect at x = 1.5 and y = 1

8 0
4 years ago
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anyanavicka [17]

Answer:

if \:  log(x )  = 3 \\  log_{10}(x)  = 3 \\   {10}^{3}  = x \\ therfore \to \:  \boxed{x =  {10}^{3} } \\ \\  if \:  log(y )  = 2 \\  log_{10}(y)  = 2 \\   {10}^{2}  = y \\ therfore \to \:  \boxed{y=  {10}^{2} }

Step-by-step explanation:

x^2 -7xy =3000y \: then \to \\ x^2 =3000y + 7xy \\ {(10 ^{3} )}^{2}  = 3000(10)^{2}    + 7( {10}^{3} \times  {10}^{2})  \\   {10}^{6}   = 3000(10)^{2}    + 7( {10}^{3} \times  {10}^{2})  \\   {10}^{6}   = 3000(10)^{2}    + 7( {10}^{5} )   \\  {10}^{6}  = 300000 + 700000 \\   \boxed{{10}^{6}  = 1000000} \\ hence \: the \: equation \to \: x^2 -7xy =3000y \\ \boxed{ is \: corret}

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3 0
3 years ago
To the nearest 1000, there are 18,000 people at a festival . Write down the minimum possible number of people at the festival
Andreyy89

Answer:

17500

Step-by-step explanation:

17499 rounds down

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8 0
3 years ago
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Valentin [98]
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4 0
4 years ago
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