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3 years ago

How do i find joint relative frequency?

1 answer:

3 0

A joint relative frequency is found by dividing a frequency that is not in the Total row or the Total column by the frequency’s row total or column total.

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A customer service representative earns $13 an hour, and he works 52 hours a week. What is his weekly wage? A. $91 B. $364 C. $6

leva [86]

I'm pretty sure its c
You just multiply 13 and 52

4 0

3 years ago

In Mr. Dixon's math class, 7 out of 20 students are in the math club. What percent of the students are in the math club?

Ganezh [65]

7/20 = 0.35
35 percent.

5 0

3 years ago

Read 2 more answers

A clothing store has a going-out-of business sale. They are selling pants for $8.99 and shirts for $3.99. You can spend as much

astraxan [27]

Answer:

Let x represents the number of pants and y represents the number of shirts.

As per the statement:

Since, a clothing store are selling pants for $8.99 and shirts for $3.99

then;

total number of Pants cost is, $8.99x and total number of Shirt cost is, $3.99

Also, it is given that: You can spend as much as $60 and want to buy at least two pairs of pants.

then, we have the equation of inequality;

$8.99x + 3.99y \leq 60$ ;......[1] where x, y are natural number.

x-intercept:

Substitute the value y= 0 in [1] and solve for x;

$8.99x + 3.99(0) \leq 60$

$8.99x \leq 60$

Simplify:

$x \leq 6.667$

Since, x is in natural number;

$x \leq 7$

Similarly.

For y-intercept:

Substitute the value x= 0 in [1] and solve for x;

$8.99(0) + 3.99y \leq 60$

$3.99y \leq 60$

Simplify:

$y \leq 15.037$

$y \leq 15$

Therefore, we have

$8.99x + 3.99y \leq 60$ ;

$2\leq x\leq 7$ and $0\leq y\leq 15$

8 0

3 years ago

Problem 15-7 (Algorithmic) Speedy Oil provides a single-server automobile oil change and lubrication service. Customers provide

rodikova [14]

Answer: There are 4 average cars in the system.

Step-by-step explanation:

Since we have given that

Arrival rate = λ = 4 cars per hour

Service rate = μ = 5 cars per hour

We need to find the average number of cars in the system.

So, Average number of cars would be

$L_q=\dfrac{\lambda^2}{\mu(\mu-\lambda)}\\\\L_q=\dfrac{4^2}{5(5-4)}\\\\L_q=\dfrac{16}{5}\\\\L_q=3.2$

So, it becomes,

$L=L_q=\dfrac{\lambda}{\mu}\\\\L=3.2+\dfrac{4}{5}\\\\L=3.2+0.8\\\\L=4$

Hence, there are 4 average cars in the system.

6 0

4 years ago

How do i graph the parabolas y = 1/32x^2

Pachacha [2.7K]

$y=\frac{1}{32}x^2 \\ \\x=-16 \Rightarrow y=\frac{1}{32} *(-16)^2=\frac{1}{\not32^1}*\not256^8=8\\ \\x=-8 \Rightarrow y=\frac{1}{32} *(-8)^2=\frac{1}{\not32^1}*\not64^2=2\\ \\x=0 \Rightarrow y=\frac{1}{32} *(0)^2=\frac{1}{\not32^1}*0=0 \\ \\x=8 \Rightarrow y=\frac{1}{32} *(8)^2=\frac{1}{\not32^1}*\not64^2=2 \\ \\x= 16 \Rightarrow y=\frac{1}{32} *( 16)^2=\frac{1}{\not32^1}*\not256^8=8$

7 0

3 years ago