The answer is D because it can only have one symmetrical line straight down the middle.
Answer:

Step-by-step explanation:
<u>Given: </u>
line y=3x-1
point (-3,0)
<u>Write:</u> equation of the line that is perpendicular to the given and passes through the point (-3,0)
<u>Solution:</u>
The slope of the given line is 
If
is the slope of perpendicular line, then

So, the equation of the needed line is 
Find b. This line passes through the point (-3,0), so its coordinates satisfy the equation:

Let z = sin(x).
.. z^2 -2z = 2
.. z^2 -2z +1 = 3
.. (z -1)² = 3
.. z -1 = ±√3
.. z = 1 -√3 . . . . . the positive solution is extraneous
sin(x) = 1 -√3
He needs 3 Tickets to Win a Prize.27×2 is... And that's ur Answer
F(x) = x4(x2 - 1)
f(-x) = (-x)4((-x)2 - 1)
f(-x) = x4(x2 - 1)
from above explanation it is clear that the function is even.