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Dafna11 [192]
3 years ago
6

Can chemicals in clouds cause a rainstorm to occur

Chemistry
1 answer:
guajiro [1.7K]3 years ago
8 0
Yes chemicals in clouds can cause rainstorms 
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Find the mass in grams of 2.65 x 10^24 molecules of cl2
Alina [70]
Moles of Cl2 = 2.65 x 10^24 / 6.02 x 10^23 = 4.4 moles.

Mass of Cl2 in grams = molar mass of Cl2 x moles of Cl2
                                     = 70.906 x 4.4
                                     = 311.98 grams.

Hope this helps!
8 0
4 years ago
Plsss help this midterm ends 12.30
Alona [7]

Answer:

We know that,

Density= mass upon volume.

mass= 21.93g

Volume= 49.3 - 46.3

= 3 cm³

Density = 21.93÷ 3

= 7.31 g/cm³

Hope it helps :))

5 0
3 years ago
If y > z, which of the following equations must be true?
marin [14]

Answer:

I think the answer is y-z>0

8 0
3 years ago
What will be the the net ionic equations for the following ones:- a) AgNO3 + KCl b) Ni(NO3)2 + Na2S c) CaCl2 + Na2CO3. 2) Write
Zielflug [23.3K]
In a) the final equation is AgNO3 + KCl = AgCl + KNO3, b) Ni(NO3)2 + Na2S = 2NaNO3 + NiS; c) CaCl2 + Na2CO3 = 2 NaCl + CaCO3. In 2) The total net equation is Ca 2+ + CO32- = CaCO3 (s). 
4 0
3 years ago
A solution contains two isomers, n-propyl alcohol and isopropyl alcohol, at 25°C. The total vapor pressure is 38.6 torr. What ar
Leona [35]

Answer:

Mole fraction of alcohols in liquid phase x_1=0.2727\& x_2=0.7273.

Mole fraction of alcohols in vapor phase y_1=0.1468\& y_2=0.8516.

Explanation:

The total vapor pressure of the solution = p =38.6 Torr

Partial vapor pressure of the  n-propyl alcohol =p^{o}_1=21.0 Torr

Partial vapor pressure of the isopropyl alcohol =p^{o}_2=45.2 Torr

p=x_1\times p^{o}_1+x_2\times p^{o}_2  (Raoult's Law)

p=x_1\times p^{o}_1+(1-x_1)\times p^{o}_2

38.6 Torr=x_1\times 21.0 Torr+(1-x_1)\times 45.2 Torr

x_1=0.2727

x_2=1-0.2727=0.7273

x_1\& x_2 is mole fraction in liquid phase.

Mole fraction of components in vapor phase y_1\& y_2

p_1=y_1\times p (Dalton's law of partial pressure)

y_1=\frac{p_1}{38.6 Torr}=\frac{p^{o}_1\times x_1}{38.6 Torr}

y_1=\frac{21.0 Torr\times 0.2727}{38.6 Torr}=0.1468

y_1=\frac{p_2}{38.6 Torr}=\frac{p^{o}_2\times x_2}{38.6 Torr}

y_2=\frac{45.2 Torr\times 0.7273}{38.6 Torr}=0.8516

Mole fraction of alcohols in vapor phase y_1=0.1468\& y_2=0.8516

5 0
3 years ago
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