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dezoksy [38]
2 years ago
7

Write the balanced molecular chemical equation for the reaction in aqueous solution for ammonium sulfate and iron(II) chloride.

If no reaction occurs, simply write only NR. ☐⁴⁻ ☐³⁻ ☐²⁻ ☐⁻ ☐⁺ ☐²⁺ ☐³⁺ ☐⁴⁺ 1 2 3 4 5 6 7 8 9 0 ☐₁ ☐₂ ☐₃ ☐₄ ☐₅ ☐₆ ☐₇ ☐₈ ☐₉ ☐₀ + ( ) → ⇌ (s) (l) (g) (aq) Ir N Fe O Am Cl NR S H Ch Reset
Chemistry
1 answer:
dusya [7]2 years ago
7 0

The balanced molecular chemical equation for the reaction is (NH4)2SO4(aq) + FeCl2(aq) -------> FeSO4(aq) + 2NH4Cl(aq).

The rule for writing a balanced chemical reaction equation is that the number of atom of each element on the right hand side must be the same as the number of atoms of the same element on the left hand side of the reaction equation. This is achieved by performing an atom count.

The balanced molecular chemical equation for the reaction in aqueous solution for ammonium sulfate and iron(II) chloride is;

(NH4)2SO4(aq) + FeCl2(aq) -------> FeSO4(aq) + 2NH4Cl(aq)

Learn more: brainly.com/question/6505878

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Positive and Negative ions attract each-other and form chemical __________
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Answer:

Changes

Explanation:

When positive and negative ions attract each other it fors a negative chemical changes

7 0
3 years ago
Which of the following is not the same as 0.00684 kg?
olchik [2.2K]

kg and all the given units are units used to measure mass.

kg is the standard unit to measure mass

lets find the value of 0.00684 kg in all the given units

a. dkg

1 kg is equivalent to 100 decagram (dkg)

therefore 0.00684 kg is = 100 dkg/kg x 0.00684 kg = 0.684 dkg

this is not the given value therefore this choice is incorrect

b. 1 kg is equivalent to 1000 g

therefore 0.00684 kg = 1000 g/kg x 0.00684 kg = 6.84 g

this is the given value so this is correct

c. 1 kg is equivalent to 100 000 centigrams (cg)

therefore 0.00684 kg = 100 000 cg/kg x 0.00684 kg = 684 cg

this is the given value so this is also correct

d) 1 kg is equivalent to 1 000 000 mg

therefore 0.00684 kg = 1 000 000 mg/kg x 0.00684 kg = 6 840 mg

this too is correct

the incorrect answer is A. 0.0684 dkg

5 0
3 years ago
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What would be the water potential of pure water at atmospheric pressure?
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An ethylene glycol solution contains 21.4 g of ethylene glycol (C2H6O2) in 97.6 mL of water. (Assume a density of 1.00 g/mL for
8090 [49]

Answer: The freezing point and boiling point of the solution are -6.6^0C and 101.8^0C respectively.

Explanation:

Depression in freezing point:

T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_f = freezing point of solution = ?

T^o_f = freezing point of water = 0^0C

k_f = freezing point constant of water = 1.86^0C/m

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

w_2 = mass of solute (ethylene glycol) = 21.4 g

w_1= mass of solvent (water) = density\times volume=1.00g/ml\times 97.6ml=97.6g

M_2 = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}

T_f=-6.6^0C

Therefore,the freezing point of the solution is -6.6^0C

Elevation in boiling point :

T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_b = boiling point of solution = ?

T^o_b = boiling point of water = 100^0C

k_b = boiling point constant of water = 0.52^0C/m

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

w_2 = mass of solute (ethylene glycol) = 21.4 g

w_1= mass of solvent (water) = density\times volume=1.00g/ml\times 97.6ml=97.6g

M_2 = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

(T_b-100)^0C=1\times (0.52^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}

T_b=101.8^0C

Thus the boiling point of the solution is 101.8^0C

4 0
3 years ago
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