Question

The heat of combustion of butane , c4h10 , is 2874 kj/mol. what is the heat of combustion of butane, in kj per gram?(provide the right sig. fig)

Answer 1

Answer : 49.45 kJ per gram.

Explanation:

Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.

Given :

Amount of heat released on combustion of butane = 2874 kJ/mol

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

1 mole of $C_4H_{10}$ weighs = 58.12 g

Thus we can say:

58.12 g of $C_4H_{10}$ on combustion releases = 2874 kJ

Thus 1 g of $C_4H_{10}$ on combustion releases =$\frac{2874}{58.12}\times 1=49.45 kJ$

Thus the heat of combustion of butane, in kJ per gram is 49.45.

Answer 2

The answer will be d i just took the test and got it correct