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Arturiano [62]
2 years ago
5

Pose two problems of everyday life where addition, subtraction, multiplication and division of integers are used​

Mathematics
1 answer:
qaws [65]2 years ago
8 0

Answer:

taxes and at work

Step-by-step explanation:

you deal with money at work and you have to calculate numbers doing taxes.

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One hose can fill a small swimming pool in 65 minutes. A larger hose can fill the pool in 35 minutes. How long will it take the
tatuchka [14]

Answer:

22.75 minutes or 22 minutes 45 seconds

Step-by-step explanation:

Okay, this is a working together question. Let’s walk through it together!

Firstly, let’s say the total volume of the swimming pool is x sq.meters

Now, the rate of the smaller hose would be x/65 while that of the larger will be x/35

Now, their combined rate would be x/65 + x/35 = 100x/2275

Now, since the volume is x, the time taken is simply, the volume divided by the joint rate. That is mathematically equal to x divided by 100x/2275

x * 2275/100x = 2275/100 = 22.75 minutes or 22 minutes 45 seconds

8 0
3 years ago
MOON The expression gives the weight of an object on the Moon in pounds with a weight of w pounds on Earth. What is the weight o
dybincka [34]

Answer: 29.7 pounds

Step-by-step explanation:

The expression in question is w/6.

If the weight of an object on earth is w, the weight of the object on the moon is w/2.

The weight of the space suit is therefore:

= 178.2/6

= 29.7 pounds

4 0
2 years ago
Statements that are true for a cylinder with radius r and height h.
vampirchik [111]

Answer:

Only the second and third statements are correct:

Doubling <em>r</em> quadruples the volume.

Doubling <em>h</em> doubles the volume.

Step-by-step explanation:

The volume of a cylinder is given by:

\displaystyle V=\pi r^2h

We can go through each statement and examine its validity.

Statement 1)

If the radius is doubled, our new radius is now 2<em>r</em>. Hence, our volume is:

\displaystyle V=\pi (2r)^2h=4\pi r^2h

So, compared to the old volume, the new volume is quadrupled the original volume.

Statement 1 is not correct.

Statement 2)

Using the previous reasonsing, Statement 2 is correct.

Statement 3)

If the height is doubled, our new height is now 2<em>h</em>. Hence, our volume is:

V=\pi r^2(2h)=2\pi r^2h

So, compared to the old volume, the new volume has been doubled.

Statement 3 is correct.

Statement 4)

Statement 4 is not correct using the previous reasonsing.

Statement 5)

Doubling the radius results in 2<em>r</em> and doubling the height results in 2<em>h</em>. Hence, the new volume is:

V=\pi (2r)^2(2h)=\pi (4r^2)(2h)=8\pi r^2h

So, compared to the old volume, the new volume is increased by eight-fold.

Statement 5 is not correct.

7 0
3 years ago
Step-by-step solution for: (√2+√10)^2
azamat
Note:  √a * √a  = a
           √a * √b  = √ab

(√2 + √10)²  =  (√2 + √10)(√2 + √10)
                    =  √2(√2 + √10) + √10(√2 + √10)
                    =   √2*√2 + √2*√10 + √10*√2 + √10*√10
                    =       2      + √20  + √20 + 10
                    =      (2 + 10) + (√20 + √20)
                    =        12 +  2√20

√20 = √(4 *5) = √4 * √5 = 2√5

                     =        12 +  2√20  = 12 + 2(2√5)
                     = 12 + 4√5
5 0
3 years ago
HELP ME ASAP WILL MARK BRAINLIEST
nataly862011 [7]

Answer:

1912

Step-by-step explanation:

3 0
3 years ago
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