All categories

3 years ago

Pose two problems of everyday life where addition, subtraction, multiplication and division of integers are used

Mathematics

1 answer:

qaws [65]3 years ago

8 0

Answer:

taxes and at work

Step-by-step explanation:

you deal with money at work and you have to calculate numbers doing taxes.

You might be interested in

Help:( i’ll give brainliest

almond37 [142]

My gut says go with 5/7

7 0

3 years ago

Sara needs 1/3 of a yard of ribbon to make a bow. She has 10 yards of ribbon. How many bows can she make?

storchak [24]

Answer:

30 Bows

Step-by-step explanation:

Every yard is 3 feet, and each bow calls for 1/3 of a yard, so a foot per bow.

So you can make 10 yards, 30 feet by multiplying by 3, and then its pretty straight forward from there. 30 / 1 = 30 Bows

8 0

3 years ago

Ay bought a guitar on sale at 45% off. The original price was $576.75.

Sindrei [870]

Answer:

$317.20

Step-by-step explanation:

hope this is right and hope it helps:D

8 0

3 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

4 years ago

Are any of these a function

Elena-2011 [213]

Answer:

Yes because the 1st and 3rd one are functions

Step-by-step explanation:

6 0

3 years ago

Pose two problems of everyday life where addition, subtraction, multiplication and division of integers are used​

Pose two problems of everyday life where addition, subtraction, multiplication and division of integers are used