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koban [17]
3 years ago
6

I’ll mark brainlist No links

Mathematics
2 answers:
mash [69]3 years ago
6 0
The answers are 9/24 28/24
taurus [48]3 years ago
4 0

Answer:

3/8 = 9/24

7/6 = 28/24

Step-by-step explanation:

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Right angles have one angle that is exactly 90 degrees and two angles that are less then 90 degrees
padilas [110]
A acute angle is the answer your looking for
6 0
3 years ago
Hich equations are true for x = –2 and x = 2? Select two options
natulia [17]

Answer:

first and fourth

Step-by-step explanation:

x² - 4 = 0 ( add 4 to both sides )

x² = 4 ( take square root of both sides )

x = ± \sqrt{4} = ± 2

that is x = - 2, x = 2

4x² = 16 ( divide both sides by 4 )

x² = 4 ( take square root of both sides )

x = ± \sqrt{4} = ± 2

that is x = - 2, x = 2

3 0
2 years ago
Which expression represents the sixth term in binomial expansion (2a-3b)^10
AysviL [449]

Therefore the sixth term in the binomial expansion is=-{10}C_5(2a)^{5} (3b)^5

Step-by-step explanation:

Given

(2a -3b)^{10}

=^{10}C_0 (2a)^{10} + ^{10}C_1(2a)^9(-3b)+^{10}C_2(2a)^8(-3b)^2+...............+^{10}C_10(-3b)^{10}

So,

T_{n+1}= ^{10}C_n(2a)^{(10-n)} (-3b)^n

T_6=T_{(5+1)} =^{10}C_5(2a)^{10-5} (-3b)^5

Therefore the sixth term in the binomial expansion is= {10}C_5(2a)^{10-5} (-3b)^5

                                                                                         =-{10}C_5(2a)^{5} (3b)^5

3 0
3 years ago
What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

8 0
3 years ago
Quadrilateral EFGH has coordinates E(a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of HG.
soldier1979 [14.2K]
Midpoint of HG = ((0 + 2a)/2, (0 + 0)/2) = (2a/2, 0/2) = (a, 0)
option D is the correct answer.
8 0
3 years ago
Read 2 more answers
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