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2 years ago

Find the missing coordinate to complete the ordered-pair solution to the given linear equation: 3x-4y=6

Mathematics

1 answer:

zavuch27 [327]2 years ago

8 0

8 is the answer if u do some equation gymnastics as i call them

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The weight of

Inga [223]

Try making a proportion 10,000/1 and then 1000/x and solve

8 0

3 years ago

. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte

Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160$

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240$

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

$\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}$

4 0

1 year ago

The perimeter of an isosceles triangle is 25cm

Reika [66]

First: 7cm, 7cm, 11cm
second: 19cm, 3cm, 3cm

3 0

3 years ago

HELP I NEED HELP ASAP

lilavasa [31]

Answer:

The answer is C

Step-by-step explanation:

The mean of math is 84, and the Mean of science is 85.

so, science is clearly one point higher

7 0

2 years ago

Factorize: a^4+2xa³+a²x²-y^4

mart [117]

Answer:

(a^2+ax-y) (a^2+ax+y^2)

Step-by-step explanation:

a^4+2xa³+a²x²-y^4

(a^2+ax)^2-y^4

(a^2+ax-y) (a^2+ax+y^2)

4 0

2 years ago

Read 2 more answers