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zavuch27 [327]
1 year ago
15

∆ABC is translated 6 units up and 3 units left to create ∆A'B'C'.

Mathematics
1 answer:
Wittaler [7]1 year ago
7 0

∆ABC is translated 6 units up and 3 units left to create ∆A'B'C' using the rule (x, y) ⇒ (x - 3, y + 6)

<h3>What is transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformations are<em> reflection, rotation, translation and dilation.</em>

Rigid transformation are those transformations that do not change the shape or size of a figure such as translation, reflection and rotation. Dilation is not a rigid transformation.

∆ABC is translated 6 units up and 3 units left to create ∆A'B'C' using the rule (x, y) ⇒ (x - 3, y + 6)

Find out more on transformation at: brainly.com/question/4289712

#SPJ

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The dimensions of one of the sails on a sailboat are 9 feet, 12 feet, and 15 feet. Is the sail a right triangle?
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yes

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Using the converse of Pythagoras' identity

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State whether the following coordinates on a Cartesian plane form an acute, obtuse or right triangle: a) (-1, 1), (7,-2) and (1,
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a) Acute triangle

b) Right triangle

Step-by-step explanation:

∵ A triangle having sides a, b and c is called,

Acute : If a² + b² > c² or a² + c² > b² or b² + c² > a²,

Obtuse : if a² + b² < c² or a² + c² < b² or b² + c² < a²

Right : a² + b² = c² or a² + c² = b² or b² + c² = a²,

a) Let A≡(-1, 1), B≡(7,-2) and C≡(1,-5),

By the distance formula,

AB=\sqrt{(7-(-1))^2+(-2-1)^2}=\sqrt{(7+1)^2+(-3)^2}=\sqrt{8^2+3^2}=\sqrt{64+9}=\sqrt{73}\text{ unit}

Similarly,

BC=\sqrt{45}\text{ unit}

CA=\sqrt{40}\text{ unit}

∵ The sum of any two sides is greater than third side,

So, ABC is a triangle,

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AB^2 + BC^2 > CA^2

⇒ ABC is an acute triangle.

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By the distance formula,

PQ = √17 unit,

QR = √17 unit,

RP = √34 unit,

∵ The sum of any two sides of PQR is greater than third side,

⇒ PQR is a triangle ,

Also,

RP^2=PQ^2+QR^2

Hence, PQR is a right triangle.

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3 years ago
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