∆ABC is translated 6 units up and 3 units left to create ∆A'B'C'.

Mathematics

1 answer:

Wittaler [7]2 years ago

7 0

∆ABC is translated 6 units up and 3 units left to create ∆A'B'C' using the rule (x, y) ⇒ (x - 3, y + 6)

<h3>What is transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformations are<em> reflection, rotation, translation and dilation.</em>

Rigid transformation are those transformations that do not change the shape or size of a figure such as translation, reflection and rotation. Dilation is not a rigid transformation.

∆ABC is translated 6 units up and 3 units left to create ∆A'B'C' using the rule (x, y) ⇒ (x - 3, y + 6)

Find out more on transformation at: brainly.com/question/4289712

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Which expression has both 8 and n as factors?

mezya [45]

Answer:

Step-by-step explanation:

8n is the factor of both 8 and n. in the following question.

Factor ⇒ If a number, that use to divide another number and we get zero as a remainder, the number is called the factor of another number.

In this question, 8n is divided by both 8 and n and also we get zero as a remainder.

Therefore, 8n is the factor of both 8 and n .

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4 years ago

In aâ€‹ lottery, 6 numbers are randomly sampled without replacement from the integers 1 to 50. Their order of selection is not i

nlexa [21]

Answer: 0.444225

Step-by-step explanation:

Given : The total number of tickets = 50

Number of tickets are randomly sampled without replacement =6

Since the order of selection is not important , so we use combinations.

Total number of ways to select 6 tickets = $^{50}C_6$

The number of winning tickets = 6

So, number of tickets that are not winning = 50-6=44

Number of ways of selecting zero winning numbers= $^{44}C_{6}$

Now , the probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket out of the 50 possible numbers would be $\dfrac{^{44}C_{6}}{^{50}C_6}$

$=\dfrac{\dfrac{44!}{6!(44-6)!}}{\dfrac{50!}{6!(50-6)!}}\\\\\\=\dfrac{\dfrac{44\times43\times42\times41\times40\times39\times38!}{38!}}{\dfrac{50\times49\times48\times47\times46\times45\times44!}{44!}}\\\\\\=\dfrac{44\times43\times42\times41\times40\times39}{50\times49\times48\times47\times46\times45}\\\\=\dfrac{252109}{567525}\approx0.444225$