The probability that he selected the special quarter is 87.5%.
<h3><u /></h3><h3><u>Probability</u></h3>
Given that Mandvil has one standard quarter and one special quarter with a Head on both sides, and he selects one of these two coins at random, and without looking at it first, he flips the coin three times, to determine, if he flips a Head three straight times, what is the probability that he selected the special quarter, the following calculation must be made:
- 1 - (standard quarter) = X
- 1 - (0.50^3) = X
- 1 - 0.125 = X
- 0.875 = X
- 0.875 x 100 = 87.5
Therefore, the probability that he selected the special quarter is 87.5%.
Learn more about probability in brainly.com/question/24217562
Answer:
B, D, D
Step-by-step explanation:
Z>-3
Z<5
Z< or = 4
These 3 above have the 3 numbers in the solution set!
You just have to test each number in each inequality, and when all 3 of them work, the inequality is a part of the solution set!
Also Thanks for the 50 Points!
Answer:
Number 1
Step-by-step explanation:
-5(m + 1) ≤ 23
Distribute
-5m - 5 ≤ 23
-5m ≤ 23 + 5
-5m ≤ 28
-m ≤ 28/5
Since we divide by a negative the ≤ flips to ≥
m ≥ -28/5
Hope this helps :3
