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Dmitriy789 [7]
3 years ago
14

What units measure heat? What factors determine heat capacity?

Chemistry
1 answer:
guajiro [1.7K]3 years ago
4 0
The heat is measured with degree Celsius and degree Fahrenheit. The heat capacity depends on both it's mass and it's chemical composition. 
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The use of evaporation and condensation to separate the partsof a mixture is called _____
Keith_Richards [23]

Answer: Evaporation Condensation is used to seperate the parts of a mixture

Explanation: This is because it is the first order of the distilation process

5 0
3 years ago
Consider the reaction at 500 ° C 500°C . N 2 ( g ) + 3 H 2 ( g ) − ⇀ ↽ − 2 NH 3 ( g ) K c = 0.061 N2(g)+3H2(g)↽−−⇀2NH3(g)Kc=0.06
Sav [38]

Answer:

Q = 0.061 = Kc

Explanation:

Step 1: Data given

Temperature = 500 °C

Kc=0.061

1.14 mol/L  N2

5.52 mol/L H2

3.42 mol/L NH3

Step 2: Calculate Q

Q=[products]/[reactants]=[NH3]²/ [N2][H2]³

If Qc=Kc then the reaction is at equilibrium.  

If Qc<Kc then the reaction will shift right to reach equilibrium.

If Qc>Kc then the reaction will shift left to reach equilibrium.  

Q = (3.42)² / (1.14 * 5.52³)

Q = 11.6964/191.744

Q = 0.061

Q = Kc the reaction is at equilibrium.  

4 0
3 years ago
The diagram shows the process of gas exchange in an animal. What happens during gas exchange in this animal?
dmitriy555 [2]

Answer:

D I think

Explanation:

3 0
3 years ago
Read 2 more answers
the pressure in a sealed plastic container is 108 kPa at 41 degrees Celsius. What is the pressure when the temperature drops to
Katarina [22]

<u>Answer:</u> The new pressure will be 101.46 kPa.

<u>Explanation:</u>

To calculate the new pressure, we use the equation given by Gay-Lussac Law. This law states that pressure is directly proportional to the temperature of the gas at constant volume.

The equation given by this law is:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are initial pressure and temperature.

P_2\text{ and }T_2 are final pressure and temperature.

We are given:

By using conversion factor:   T(K)=T(^oC)+273

P_1=108kPa\\T_1=41^oC=314K\\P_2=?kPa\\T_2=22^oC=295K

Putting values in above equation, we get:

\frac{108kPa}{314K}=\frac{P_2}{295K}\\\\P_2=101.46kPa

Hence, the new pressure will be 101.46 kPa.

3 0
3 years ago
In uncompetitive inhibition, the inhibitor can bind to the enzyme only after the substrate binds first. (T/F)
Veronika [31]

Answer:

True

Explanation:

In an uncompetitive inhibition, initially the substrate [S] binds to the active site of the enzyme [E] and forms an enzyme-substrate activated complex [ES].

The inhibitor molecule then binds to the enzyme- substrate complex [ES], resulting in the formation of [ESI] complex, thereby inhibiting the reaction.

This inhibition is called uncompetitive because the inhibitor does not compete with the substrate to bind on the active site of the enzyme.

Therefore, in an uncompetitive inhibition, the inhibitor molecule can not bind on the active site of the enzyme directly. The inhibitor can only bind to the enzyme-substrate complex formed.

       

4 0
3 years ago
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