Alright, so for AB and CD to be parallel, CX and DX would have to be equal, as is with AX and BX. In addition, for CD and AB to be parallel, all sides in both triangles are either equal or not all sides in even one triangle are equal. Therefore, CD is not 3. In addition, two sides of a triangle combined must be greater than the third, so that leaves 5, 4, and 2 for CD. If it was 5, that would mean that all sides are equal, so that leaves 4 and 2. However, I don't see anything to prove either one right, sorry:/
There are 30 students all together, and 4 of them are Freshman girls (Freshwomen ?). So the probability that one randomly chosen student is a Female Frosh is 4/30 = 2/15.
Answer:
Step-by-step explanation:
Hello,
a and b are the zeros, we can say that
So we can say that
Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b
for instance we can write
and we can notice that
so
![(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab](https://tex.z-dn.net/?f=%28x-2a-3b%29%28x-3a-2b%29%3Dx%5E2-5%28a%2Bb%29x%2B6%5B%28a%2Bb%292-2ab%5D%2B13ab%5C%5C%3D%20x%5E2-5%28a%2Bb%29x%2B6%28a%2Bb%29%5E2%2Bab)
it comes
multiply by 3
Answer:
Raise the power
Step-by-step explanation:
Hmm, I think your answer would be 3x ≥ -6
Let me know if this helps!
