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Lunna [17]
3 years ago
7

Susie is thinking about changing her auto insurance policy at Fret-No-More Auto Insurance. Her current policy includes the follo

wing options: $50/100,000 limit for bodily injury, $25,000 limit for property damage, $250 deductible for collision, and $50 deductible for comprehensive. Which of the following changes would increase Susie’s limits the most without increasing her monthly premium by more than $5.00?
Mathematics
2 answers:
Katen [24]3 years ago
8 0

Answer:

C. Increase coverage on bodily injury to $100/300,000 and on property damage to $50,000

Step-by-step explanation:

elena55 [62]3 years ago
5 0
From her current policy which includes the $50/100,000 limit for bodily injury, $25,000 limit for property change, $250 deductible for collision, and $50 deductible for comprehensive. To increase Susie’s limits the most without increasing her monthly premium by more than $5.00 she should: 

Increase coverage on bodily injury to $100/300,000 and on property damage to $50,000.


<span>I hope this helps, Regards.</span>
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Find the standard form polynomial that represents this product. (6 - y - 4y^2)(-5 + 7y^2)​
Tema [17]

Answer:

  • -28y^4 - 7y^3 + 62y^2 + 5y - 30

Step-by-step explanation:

<u>Opening the parenthesis and simplifying by combining like terms:</u>

  • (6 - y - 4y^2)(-5 + 7y^2)​  =
  • 6(-5) +6(7y^2) - y(-5) -y(7y^2) -4y^2(-5) -4y^2(7y^2) =
  • -30 + 42y^2  + 5y - 7y^3 +20y^2 -28y^4 =
  • -28y^4 - 7y^3 + 62y^2 + 5y - 30

5 0
4 years ago
What is the 3rd term of the linear sequence below: <br><br> 22,18,14,10,6...
Ratling [72]
Answer:

14


step by step explanation:

14
4 0
3 years ago
HELPPPPP
OlgaM077 [116]

Answer:

Point on Midline (0,3)

Maximum (9π/2,3)

Minimum (-9π/2,-3)

Step-by-step explanation:

in the given sine function which is in the form of f(x) = a sin(bx+c) +d

a = amplitude

period = frequency = 18π

Therefore b = 2π/18π = 1/9

Y intercept = vertical shift = 3

Horizontal shift = d = 0

Therefore the sine function will be

f(x) = 6 sin(x/9) + 3

Now first point on the midline is (0,3)

Second point is maximum (9π/2,9)

Third point be a minimum value ( -9π/2,-3)

7 0
3 years ago
QUESTION 2. the feasible region shows the number of chairs x and tables y that a furniture company can build each week.
GalinKa [24]

Answer:

Part a) The company can not build 12 chairs and 5 tables

Part b) The company can build 18 chairs and 3 tables

Part c) The company  can build 12,13,14,15,16 or 17 chairs

Step-by-step explanation:

we know that

If a ordered pair is a solution, then the ordered pair must be belong to the feasible region of the graph

Part a) Can the company build 12 chairs and 5 tables?

In this problem we have the ordered pair A(12,5)

Plot  and verify if the point belong to the feasible region of the graph

see the attached figure to better understand the problem

The point A is not on the feasible region

therefore

The company can not build 12 chairs and 5 tables

Part b) Can the company build 18 chairs and 3 tables?

In this problem we have the ordered pair B(18,3)

Plot  and verify if the point belong to the feasible region of the graph

see the attached figure to better understand the problem

The point B is on the feasible region

therefore

The company can build 18 chairs and 3 tables

Part c) One week, the company decides to build 4 tables. how many chairs can the company build?

For y=4

Find the value of x in the graph

The solutions point for y=4 tables are

(12,4), (13,4),(14,4),(15,4),(16,4) and (17,4)

therefore

The company  can build 12,13,14,15,16 or 17 chairs

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an older person is three years older than seven times the age of a younger person the sum of their ages is 43 find their ages
ruslelena [56]

Step-by-step explanation:

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6 0
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