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Aloiza [94]
4 years ago
7

From the 11

Mathematics
1 answer:
elena55 [62]4 years ago
4 0
Selecting r objects out of n objects, can be done in C(n, r) many ways.

For example selecting groups of 4 people out of 10 people can be done in
C(10, 4) many ways.


C(n, r) is calculated as follows: C(n, r)= \frac{n!}{r!(n-r!)}, 

where n! is 1*2*3*...*(n-1)*n


3 men out of 11 men, and 2 women out of 6 women are to be selected.

This can be done in C(11, 3) and C(6,2) ways respectively.

Since any of the selected men group can be combined with any of the selected women group, there are C(11, 3)*C(6,2) many ways of selecting the team of 5.


C(11, 3)*C(6,2) = \frac{11!}{8!3!} * \frac{6!}{4!2!}= \frac{11*10*9*8!}{8!*3!}* \frac{6*5*4!}{4!*2!}= \frac{11*10*9}{3*2*1} * \frac{6*5}{2*1}=

165*15=2475


Answer: 2475

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unfortunately, I don't know why that isn't one of your answers, so sticking with the positive 2 I would choose y+2=- (- 3) if I were you. Looks like the -4/5 disappeared somehow?

Hope this helps

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