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Nady [450]
3 years ago
15

Trying to get down with summer school today and I’ve done most of it but a few.

Mathematics
1 answer:
Mrac [35]3 years ago
7 0
When you go one month to the right in the picture, the height increases by 2, so the growth per month is 2 inches.

The starting height is 6 inch (at x=0), so a formula for f(x) = 2x + 6

f(10) = 2*10+6 = 26

Answer C is the correct one.
You might be interested in
X/6=36/24 what value of x makes this proportion true
Stolb23 [73]
Cross multiply or just multiply both sides by 24
24x/6=36
4x=36
divide both sides by 4
x=9
4 0
3 years ago
Read 2 more answers
I need help with numbers 1-4 please if someone could help me
laila [671]
You can use the slope formula or just calculate
\frac{rise}{run}
So for the first problem you run 3 units right and rise 5 units so
\frac{rise}{run}  =  \frac{5}{3}
2. Notice the y axis goes by 2 units.
\frac{ - 10}{4}  =  \frac{ - 5}{4}
3.
\frac{0}{12}  = 0
4.
\frac{2}{0}  = undefined
Please let me know if you have questions
3 0
3 years ago
A student said we cannot subtract 1.97 from 20 because one 1.97 has two decimal digits and 20 has none do you agree with this st
Pie

Answer: We can

Step-by-step explanation: 20.00

                                         -      1.97

                                             

5 0
3 years ago
How do you do 4x - 9 = 6x - 13? what do you subtract from both sides?
ohaa [14]
To start, you need to subtract 4x from both sides, that way, x is one one sid of the equation.

8 0
3 years ago
Read 2 more answers
A rectangle initially has width 7 meters and length 10 meters and is expanding so that the area increases at a rate of 8 square
Tems11 [23]

Answer:

The length of rectangular is increasing at a rate 0.5714 meters per hour.

Step-by-step explanation:

We are given the following in the question:

Initial dimensions of rectangular box:

Length,l = 10 m

Width,w = 7 m

\dfrac{dA}{dt} = 8\text{ square meters per hour}\\\\\dfrac{dw}{dt} = 40\text{ centimeters per hour} =0.4\text{ meters per hour}

We have to find the rate of increase of length.

Area of rectangle =

A = l\times w

Differentiating we get,

\displaystyle\frac{dA}{dt} = \frac{dl}{dt}w + \frac{dw}{dt}l

Putting values, we get,

8 = \dfrac{dl}{dt}(7) + (0.4)(10)\\\\\dfrac{dl}{dt}(7) = 8 -4\\\\\dfrac{dl}{dt} \approx 0.5714

Thus, the length of rectangular is increasing at a rate 0.5714 meters per hour.

5 0
2 years ago
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