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2 years ago

In th fig , d is the mid point of ab and cd is perpendicular to ab. prove abc is congurence to bcd.

Mathematics

1 answer:

Alchen [17]2 years ago

3 0

Statement Reason

-------------------------------------------------------------------------------------

1. CD=DC Reflexive Property

2. D-midpoint of AB Given

3. AD=BD Definition of Midpoint

4. CD⊥AB Given

5. m<CDA=m<CDB Definition of Perpendicular Lines

6. ΔACD≅ΔBCD SAS

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Trigonometry

Mashcka [7]

The area of the triangle EFG is 7.4 square units.

Explanation:

Given that the measurements of the sides of the triangle are EF = 8, EG = 8 and $m\angle E=22^{\circ}$

We need to determine the area of the triangle EFG

<u>Area of the triangle:</u>

The area of the triangle EFG can be determined using the formula,

$\text {Area}=\frac{1}{2} fg \sin E$

Substituting the values, we get,

$\text {Area}=\frac{1}{2} (5)(8) \sin 22^{\circ}$

Simplifying the values, we have,

$\text {Area}=\frac{1}{2}(40)(0.37)$

Multiplying, we get,

$\text {Area}=\frac{14.8}{2}$

Dividing, we get,

$\text {Area}=7.4$

Hence, the area of the triangle EFG is 7.4 square units.

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2 years ago

Help me please, thank you! :)

EastWind [94]

Answer:

It's 16 units. Just look at the lengths and how many times they are on a shape. The shape is a rectangle, which means there will be two of each length, so just add them all together. 6+6+2+2=16

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3 years ago

On the diagram, two angles (<1 and <2) formed by the road, and the borders are congruent.

iren [92.7K]

Answer: they share a road lol

Step-by-step explanation:

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3 years ago

Read 2 more answers

A Square has an area of 324cm^2 . What is the squares’s perimeter?

a_sh-v [17]

Answer:

72cm

Step-by-step explanation:

A=a^2

p=4a

p=4√A=4x√324=72 cm

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2 years ago

Good afternoon!

Vladimir [108]

9514 1404 393

Answer:

5) 112°

6) 40°

Step-by-step explanation:

5) The angle E or ? is half the sum of the intercepted arcs:

? = (130° +94°)/2 = 112°

6) The angle D is half the difference of the intercepted arcs:

? = (135° -55°)/2 = 40°

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2 years ago

In th fig , d is the mid point of ab and cd is perpendicular to ab. prove abc is congurence to bcd.​

In th fig , d is the mid point of ab and cd is perpendicular to ab. prove abc is congurence to bcd.