Answer:
The standard deviation of the sampling distribution of sample means would be 0.8186.
Step-by-step explanation:
We are given that
Mean of population=23.2 pounds
Standard deviation of population=6.6 pounds
n=65
We have to find the standard deviation of the sampling distribution of sample means.
We know that standard deviation of the sampling distribution of sample means
=
Using the formula
The standard deviation of the sampling distribution of sample means
=

Hence, the standard deviation of the sampling distribution of sample means would be 0.8186.
Principal = Rs 4000
Amount = Rs 6000
Time = 2 years
Rate = ?
Amount = principal + simple interest
Rs 6000 = Rs 4000 + simple interest
simple interest = Rs 6000 - Rs 4000 = Rs 2000
Simple interest = P*R*T/100
Rs 2000 = Rs 4000* R*2/100
R = 100/4 = 25%
First find the area of the triangle: (4 x 6) ÷ 2 = 12
Then the area of the rectangle: 6 x 8 = 48
Last combine: 48 + 12 = 60
Lol, sorry~
Hope this helped tho
Distribute the 3 to 4m and 6. this makes 12m-18=12
now add 18 to both sides.
12m=30
now divide by 12
m=30/12