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3 years ago

In th fig , d is the mid point of ab and cd is perpendicular to ab. prove abc is congurence to bcd.

Mathematics

1 answer:

Alchen [17]3 years ago

3 0

Statement Reason

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1. CD=DC Reflexive Property

2. D-midpoint of AB Given

3. AD=BD Definition of Midpoint

4. CD⊥AB Given

5. m<CDA=m<CDB Definition of Perpendicular Lines

6. ΔACD≅ΔBCD SAS

Read more about excel formulas at:

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8 0

2 years ago

The pair of values below is from a direct variation. Find the missing number.

NISA [10]

Answer:

The answer is 2.

2 since 6/4=3/2

Step-by-step explanation:

Since your relation is a direct variation then the points on your line are of the form y=kx where k is the constant of variation (also called constant of proportionality)

If y=kx then y/x=k.

So all the points in this relation since it is a direct variation will be equal to y-coordinate/x-coordinate.

So we are going to solve this proportion:

$\frac{6}{4}=\farc{3}{x}$

Again I put y/x from each point. They should have same ratio because this is a direct variation.

Cross multiply:

$6(x)=4(3)$

$6x=12$

Divide boht sides by 6:

$x=\frac{12}{6}$

$x=2$

6 0

3 years ago

Read 2 more answers

The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equatio

maria [59]

Your answer is A i believe

3 0

3 years ago

Read 2 more answers

Find y using Pythagorean theorem or proportion

Tcecarenko [31]

We have three similar triangles, let's see if we can get this right, right vertex first, then other vertex from small side:

EDF ~ GDE ~ GEF

As ratios that means

ED:DF:EF = GD:DE:GE = GE:EF:GF

x:20:y = 5:x:GE = GE:y:15

Since we're after y we choose

20/y = y/15

20(15) = y²

y² = 300

y = 10√3

y ≈ 17.32

4 0

3 years ago

HELP ASAP:

tekilochka [14]

Answer:

Here's how I would do it.

Step-by-step explanation:

If two triangles are similar, corresponding sides are in the same ratio.

We know the measures of b and a, so we can calculate the ratio b/a.

d and b are in the same ratio, so

$\begin{array}{rcl}\dfrac{d}{c}& = & \dfrac{b}{a}\\d & = & c \times \dfrac{b}{a}\\\end{array}$

We know the measures of c, b, and a, so we can calculate the value of d.

5 0

3 years ago

In th fig , d is the mid point of ab and cd is perpendicular to ab. prove abc is congurence to bcd.​

In th fig , d is the mid point of ab and cd is perpendicular to ab. prove abc is congurence to bcd.