Question

At what projection angle will the range of a projectile equal to 6 times its maximum height?

Answer 1

I not sure but it might be 60 kilogrames

Answer 2

The formula for maximum height is:

H = v²sin²θ/2g

The formula for range is:

R = v²sin(2θ)/g

The relationship between the two is written as:
R = 6H
v²sin(2θ)/g = 6(v²sin²θ/2g)
v²sin(2θ)/g = 3v²sin²θ/g)
Cancelling out like terms,
sin(2θ) = 3sin²θ
Solving for θ using a scientific calculator,
θ = 33.7°