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2 years ago

What is the y-intercept of the line connecting (1,5) and (4,14)?

1 answer:

7 0

The answer is C. b=2.
I found the answer by first finding the slope. To find the slope i found the difference of the y values and divided that by the difference of the x values.
14-5/4-1
This simplifies down to:
9/3 which equals 3.
I then plugged this into the slope intercept form: y=mx+b to get y=3x+b
The next step would be to plug in the values of one of the points to solve for b. The point I choose was (1,5). By plugging this point into the equation i got 5=3(1)+b which simplifies to 5=3+b which means that b=2

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3(x-2)+4(x-2)-5(x-2)

Stels [109]

Answer:

2x - 4

Step-by-step explanation:

5 0

3 years ago

Factor 80t - 16t = 0<br><br> help?

Alinara [238K]

I don't know if that is factor-able. It looks like you could just subtract and get 64t. which would lead to the answer being zero since you divide by zero when isolating the variable t.

6 0

3 years ago

Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the

sp2606 [1]

Given:

The given quadratic polynomial is :

$x^2-x-12$

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

$x^2-x-12$

Equate the polynomial with 0 to find the zeroes.

$x^2-x-12=0$

Splitting the middle term, we get

$x^2-4x+3x-12=0$

$x(x-4)+3(x-4)=0$

$(x+3)(x-4)=0$

$x=-3,4$

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

$x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}$

$x^2-(3+(-4))x+(3)(-4)$

$x^2-(-1)x+(-12)$

$x^2+x-12$

Therefore, the required polynomial is $x^2+x-12$ .

4 0

3 years ago

Eric is studying people's typing habits. He surveyed 525 people and asked whether they leave one space or two spaces after a per

Otrada [13]

Answer: (0.8115, 0.8645)

Step-by-step explanation:

Let p be the proportion of people who leave one space after a period.

Given: Sample size : n= 525

Number of people responded that they leave one space. =440

i.e. sample proportion: $\hat{p}=\dfrac{440}{525}\approx0.838$

z-score for 90% confidence level : 1.645

Formula to find the confidence interval :

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$0.838\pm (1.645)\sqrt{\dfrac{0.838(1-0.838)}{525}}\\\\=0.838\pm (1.645)\sqrt{0.00025858285}\\\\=0.838\pm (1.645)(0.01608)\\\\= 0.838\pm0.0265\\\\=(0.838-0.0265,\ 0.838+0.0265)\\\\=(0.8115,\ 0.8645)$

Hence, a 90% confidence interval for the proportion of people who leave one space after a period: (0.8115, 0.8645)

3 0

3 years ago

Date:

Nadusha1986 [10]

Answer:

#3 1/6, 1/6, 1/2, 1/3, 5/6.

#4 3/12, 4/12, 5/12, 8/12, 9/12

Step-by-step explanation:

#3 is numbers out of six (fractions).

#4 is the same thing. You add all of the numbers (4, 3, and 5) to get the total and then you subtract to get the probability.

These are all I know.

7 0

3 years ago