Interesting problem.
First - let's figure cost of each uniform at purchase.
3,000/40 = $75 each
When some uniforms were returned at $40 - there was a difference of $35 in what they paid and what they rec'd in return. ($75 - 35 = $40)
Answer:
B is True
A, C. D are false
Step-by-step explanation:
Given :
Sample size, n = 120
Mean diameter, m = 10
Standard deviation, s = 0.24
Confidence level, Zcritical ; Z0.05/2 = Z0.025 = 1.96
The confidence interval represents how the true mean value compares to a set of values around the mean computed from a set of sample drawn from the population.
The population here is N = 10000
To obtain
Confidence interval (C. I) :
Mean ± margin of error
Margin of Error = Zcritical * s/sqrt(n)
Margin of Error = 1.96 * 0.24/sqrt(120)
Confidence interval for the 10,000 ball bearing :
10 ± 1.96 * (0.24) / sqrt(120)
Hence. The confidence interval defined as :
10 ± 1.96 * (0.24) / sqrt(120) is the 95% confidence interval for the mean diameter of the 10,000 bearings in the box.
Looks like you just evaluated the summand for the given value of
, whereas the question is asking you to find the value of the sum for the first
terms.
Let
. Then
is the
th partial sum.
happens to be the first term in the series, which is why that box is marked correct:
But the next partial sum is not correct:
and this is not the same notion as the second term (which indeed is 0.75) in the series.
To decrease this amount by 15% we must first find out what is 15% percent.
We can do that by multiplying the decimal of 15% by 120
15% = 0.15
0.15 x 120 = 18
So 18 is 15% of 120.
Wait! that's not the answer. We are asked to decrease by 15%
So 120 - 18 = 102
Your answer is £102
Answer:
X= -3/2
Step-by-step explanation:
6x/6=-9/6
