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Ber [7]
3 years ago
7

The city school district is considering increasing class size in the elementary schools. However, some members of the school boa

rd are concerned that larger classes may have a negative effect on student learning. In words, what would the null hypothesis say about the effect of class size on student learning?
Mathematics
1 answer:
Snezhnost [94]3 years ago
6 0

Answer:

The null hypothesis would say that class size has no effect on students learning.

Step-by-step explanation:

Null hypothesis is a type of hypothesis that is used in statistics which proposes that there is no difference between a certain characteristic of a population or the data - generating process.

Now, in this question,the school district is considering increasing class size in the elementary schools but we want to check whether larger classes may have a negative effect on students learning.

Thus, the null hypothesis would reject this claim of larger classes having negative effect on students and say that class size has no effect on students learning.

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I need help so bad please !!???
malfutka [58]

Answer:

i think it's a 41% frequency

Step-by-step explanation:

add up the numbers of the democrats, 116, and divide 48 by 116. that equals 0.41 or 41 percent

7 0
2 years ago
a hotel survey shows that nearly 30% of the guest staying at the hotel were there for personal reasons. the remainder of the gue
kondor19780726 [428]

Answer:70% is the rest

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the sum of the series and show your process for finding each term leading to the final sum.
Crazy boy [7]

ANSWER

\sum_{k=3}^5( - 2k + 5) =  - 9

EXPLANATION

The given series is

\sum_{k=3}^5( - 2k + 5)

This series is finite.

The expanded form is

\sum_{k=3}^5( - 2k + 5) = ( - 2 \times 3 + 5) + ( - 2 \times 4 + 5) + ( - 2 \times 5 + 5)

This simplifies to

\sum_{k=3}^5( - 2k + 5) = ( - 6 + 5) + ( - 8+ 5) + ( - 10+ 5)

\sum_{k=3}^5( - 2k + 5) = ( - 1) + ( - 3) + ( - 5)

\sum_{k=3}^5( - 2k + 5) =  - 9

5 0
2 years ago
George and Chin work as landscapers. George charges $90 for a 6-hour job. Chin charges $84 for the same job.The table shows thei
gulaghasi [49]
The equation must equal 84, so you can eliminate B and D.

Chin charges a rate for 2 hours, then charges a reduced rate for 4 hours. There are no discounts present in his rate, so you can eliminate A.

The equation for Chin's charges can be found by the equation C. 2x + 4y = 84.
7 0
3 years ago
Read 2 more answers
The Washington, DC, region has one of the fastest-growing foreclosure rates in the nation, as 15,613 homes went into foreclosure
Ilia_Sergeevich [38]

Answer:

a) 0.6226 = 62.26% probability that in a given year, fewer than 2 out of 100 houses in the Washington, DC area will go up for foreclosure.

b) 0.7837 = 78.37% probability that in a given year, fewer than 2 out of 100 houses in the nation will go up for foreclosure.

c) The proportion of foreclosures in the Nation is lower than in Washington, which means that with a sample size of 100, it is likely to have a small number(fewer than 2) of foreclosures than Washington DC.

Step-by-step explanation:

For each home, there are only two possible outcomes. Either it goes into foreclosure, or it does not. The probability of a home going into foreclosure is independent of other homes. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

a. What is the probability that in a given year, fewer than 2 out of 100 houses in the Washington, DC area will go up for foreclosure?

The foreclosure rate is 1.31% for the Washington, DC area, which means that p = 0.0131

We wanto to find, with n = 100:

P(X < 2) = P(X = 0) + P(X = 1)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{100,0}.(0.0131)^{0}.(0.9869)^{100} = 0.2675

P(X = 1) = C_{100,1}.(0.0131)^{1}.(0.9869)^{99} = 0.3551

P(X < 2) = P(X = 0) + P(X = 1) = 0.2675 + 0.3551 = 0.6226

0.6226 = 62.26% probability that in a given year, fewer than 2 out of 100 houses in the Washington, DC area will go up for foreclosure.

b. What is the probability that in a given year, fewer than 2 out of 100 houses in the nation will go up for foreclosure?

Foreclosure rate of 0.87% for the nation, which means that p = 0.0087. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{100,0}.(0.0087)^{0}.(0.9913)^{100} = 0.4174

P(X = 1) = C_{100,1}.(0.0087)^{1}.(0.9913)^{99} = 0.3663

P(X < 2) = P(X = 0) + P(X = 1) = 0.4174 + 0.3663 = 0.7837

0.7837 = 78.37% probability that in a given year, fewer than 2 out of 100 houses in the nation will go up for foreclosure.

c. Comment on the above findings.

The proportion of foreclosures in the Nation is lower than in Washington, which means that with a sample size of 100, it is likely to have a small number(fewer than 2) of foreclosures than Washington DC.

7 0
3 years ago
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