9514 1404 393
Answer:
variation is NOT direct
Step-by-step explanation:
The +1 tells you the variation is not direct. The equation of direct variation is of the form ...
y = kx
with nothing added.
So first you need to find a formula for who has what!
Because nobody said what chase had, chase is our variable!
Chase = x
Sophie = x-6 (six less than Chase so subtraction)
Jonah = x•3 (three times the amount of Chase)
Now you will put all of this in an equation- adding everybody together! The total is 89 so that will be what’s after the equal sign!
Your equation: x+x-6+x•3=89
First you will use PEMDAS, since there are no parentheses or exponents- you’ll do multiplication first!
x+x-6+(x•3)=89
When you multiply that out, you will be left with: x+x-6+3x=89
Second you will add all common terms! Remember- the 3x means there are THREE x’s in that one spot. Take out all x’s in the equation and add them together!
x+x+3x=5x
Now you are left with:
5x-6=89
Now you will solve this like a regular equation! First, you have to move the -6 to the right so you will do the inverse operation (the opposite sign) and add 6 to both sides! 89+6 is 95 and -6+6 is 0, so the 6 on the left cancels out and isn’t there anymore!
Now you have 5x=95. To get the x by itself, you will divide both sides by 5! (Once again, doing the inverse operation! Since 5 and x are being multiplied, you have to divide.)
When you divide, you are left with x=19. In this question, the answer is:
Each person has $19.
its A
Step-by-step explanation:
Answer:
620.14
Step-by-step explanation:
Original Equation:
Calculate exponents
Simplify:
Add like terms
Divide both sides by 7.012
Ok here's what I make of this: you're in calculus and you're working with functions and their first derivatives, which are the position function and the velocity function, respectively. You need to figure out what the functions are so you can solve the problem. But the acceleration due to gravity goes into the velocity function as -32t; in the position function, the antiderivative of velocity, it goes in as -16t^2. The position function is s(t) = -16t^2 + 48t + 400. When you solve that for t, what you get is the time the rock hits the ground. When you find that t value, sub it into the velocity equation to find the velocity at that time the rock hits the ground. Solving for t (using the quadratic equation) you get a t value of 6.720153. The velocity equation, the first derivative, is v(t) = -32t + 48. Subbing the t value of 6.720153 in you get that the velocity is -167.045. Negative is correct here as well because it was positive going up and now it's coming down.
