The slopes of perpendicular lines are negative reciprocals.The slope of the given line is 4.The slope of the perpendicular is -1/4.
Now we need to find the equation of a line that has slope -1/4 and passes through the point (4, 20).
We use the point-slope form of the equation of a line, where m = slope, and the point is (x1, y1).
y - y1 = m(x - x1)
y - 20 = -1/4(x - 4)
-4y + 80 = x - 4
x + 4y = 84
C r = (n!)/(r!(n-r)!)
9 C 3 = (9!)/(3!*(9-3)!)
9 C 3 = (9!)/(3!*6!)
9 C 3 = (9*8*7*6!)/(3!*6!)
9 C 3 = (9*8*7)/(3!)
9 C 3 = (9*8*7)/(3*2*1)
9 C 3 = (504)/(6) 9 C 3 = 84
8 is the answer because it goes 11 and if you add 8 it becomes 19 add 8 it becomes 27 add 8 35 add 8 43
Answer:
The answer to your question is: letter B
Step-by-step explanation:
Data
A (-5, 4)
B (4, 1)
Formula
slope = m = 
m = 
= 
Point slope
(y - 4) = 
(x + 5)
They lie in the same plane is the answer ;)
