Find vector parametric equation for the line through the point p=(−2,−2,−2)p=(−2,−2,−2) perpendicular to the plane x−y+z=3x−y+z=
1 answer:
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Answer: 7) Max: y = 52
8) Min: y = -51
<u>Step-by-step explanation:</u>
The Max/Min is the y-value of the intercept.
- Max is when the a-value is negative.
- Min is when the a-value is positive.
First, find the x-value of the vertex using the Axis of Symmetry formula:
x = -b/2a. Then plug the x-value into the equation to find the y-value.
7) y = -2x² - 16x + 20
↓ ↓ ↓
a= -2 b= -16 c=20
Max: y = -2(-4)² - 16(-4) + 20
= -2(16) + 64 + 20
= -32 + 84
= 52
*********************************************************************************************
7) y = x² + 12x - 15
↓ ↓ ↓
a= 1 b= 12 c= -15
Max: y = (-6)² + 12(-6) - 15
= 36 - 72 - 15
= 36 - 87
= -51