Find vector parametric equation for the line through the point p=(−2,−2,−2)p=(−2,−2,−2) perpendicular to the plane x−y+z=3x−y+z=
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The equation of a line that passes through 
and has a slope of m is 
so given the point (3,1) and slope -2
(3,1), (x1,y1)
x1=3
y1=1
m=-2
the equation is
so given the point (3,1) and slope -2
(3,1), (x1,y1)
x1=3
y1=1
m=-2
the equation is