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2 years ago

How do I Solve for h A=9h,h=

Mathematics

1 answer:

Blizzard [7]2 years ago

3 0

Answer:

h = height of the shape

Step-by-step explanation:

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Which statement corresponds to the values of x shown on the following number line? (Gray line is answer, dark black line is just

PSYCHO15rus [73]

Answer:

a)-4 5×<2

Step-by-step explanation:

<h3>#CarryOnLearning</h3>

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2 years ago

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Otrada [13]

Step-by-step explanation:

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2 years ago

Segment XY bisects angle WXZ and angle mZXY = 37 degrees. Find angle mWXY and angle mZXW

Vadim26 [7]

we know that

The angle bisector, is the line or line segment that divides the angle into two equal parts.

in this problem

m∠ZXW=m∠WXY+m∠ZXY

m∠WXY=m∠ZXY

Part a) Find the value of m∠WXY

m∠ZXY=37°-----> given value

m∠WXY=m∠ZXY=37°

therefore

the answer part a)

The measure of angle WXY is equal to 37°

Part b) Find the value of m∠ZXW

m∠ZXW=m∠WXY+m∠ZXY

m∠ZXW=37°+37°=74°

therefore

the answer part b) is

the measure of angle ZXW is 74 degrees

8 0

2 years ago

Work out m and c for the line: 3 y + 6 x = − 3

Usimov [2.4K]

Answer:

m is -2 and c is -1

Step-by-step explanation:

• Let's first phrase out the general equation of a line

${ \rm{y = mx + c}}$

m is the slope
c is the y-intercept

[ remember that a general line equation must be in slope - intercept form as shown above ]

• from our question, we are given the equation;

${ \rm{3y + 6x = - 3}}$

• let's make y the subject in order to make the equation in slope - intercept format.

→ remember to apply "subject making knowledge"

${ \rm{3y = - 3 - 6x}} \\ \\ { \rm{3y = - 6x - 3}} \\ \\ { \rm{ \frac{3y}{3} = \frac{ - 6x}{3} - \frac{3}{3} }} \\ \\ { \boxed{ \rm{y = - 2x - 1}}}$

• The above boxed equation is now a general equation. Let's extract out slope, m and y-intercept, c

${ \rm{m \: \dashrightarrow \: - 2}} \\ \\ { \rm{c \: \dashrightarrow \: - 1}}$

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3 years ago

If sec theta = - √30 / 3, find cos theta. if sin(-theta) = -0.97, find cos (π/2 - theta).

Cloud [144]

Step-by-step explanation:

$\cos \theta = \frac{1}{ \sec\theta } = - \frac{3}{ \sqrt{30} } = - \frac{3 \sqrt{30} }{30} = - \frac{ \sqrt{30} }{10}$

$\cos( \frac{\pi}{2} - \theta )= \cos \frac{\pi}{2} \cos \theta + \sin \frac{\pi}{2} \sin \theta$

Note that

$\sin( - \theta) = - \sin \theta$

$\cos \frac{\pi}{2} = 0 \: \: \: \: \: \sin \frac{\pi}{2} = 1$

Therefore,

$\cos( \frac{\pi}{2} - \theta ) = 0.97$

5 0

3 years ago