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Rufina [12.5K]
2 years ago
9

The quantities xx and yy are proportional. Xx yy 1111 1\dfrac{2}{9}1 9 2 ? 2121 2\dfrac{1}{3}2 3 1 ? 4545 55 Find the constant o

f proportionality (r)(r) in the equation y=rxy=rx. R = r=
Mathematics
1 answer:
cluponka [151]2 years ago
7 0

Answer:

Given the table:

x                         y

11                1\frac{2}{9} = \frac{11}{9}

21               2\frac{1}{3}=\frac{7}{3}

45                        5

Since, the quantity x and y are proportional.

Proportional states that:

if y varies directly to x, then equation is of the form y = rx where r is the constant of proportionality.

We have to find the value of r:

Consider any value of x and y from the given table:

Let x = 11 and y = \frac{11}{9}

Substitute the given values we get;

\frac{11}{9} = r \times 11

Divide both sides by 11 we get;

r = \frac{1}{9}

Therefore, the value of constant of proportionality r = \frac{1}{9}



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