You need to multiply 30 by 6 so 30times6 =your answer
7.2>0.9(n+8.6)
multiply 0.9 by all in parentheses
7.2> (0.9*n) + (0.9*8.6)
7.2> 0.9n + 7.74
subtract 7.74 from both sides
-0.54> 0.9n
divide both sides by 0.9
-0.6> n
ANSWER: -0.6> n
Hope this helps! :)
Answer: p
c
Step-by-step explanation:
Answer:
Since the calculated z =-3.5357 falls in the critical region z ≥ 1.645 we reject H0 and conclude that the sample provides sufficient evidence to indicate that the true percentage of all firms that announced one or more acquisitions during the year 2000 is ≥ 30%
Step-by-step explanation:
<u><em>Testing hypothesis about a population proportion when sample size is large.</em></u>
If the sample size is large then the variable
z= p^-p / sqrt [pq/n]
is approximately standard normal.
Formulate the hypotheses as
H0 : p < 30% against the claim Ha: p ≥ 30%
Choose the significance level ∝= 0.05
the critical region is z ≥ 1.645 because the alternative hypothesis is stated on a greater than or equal to basis.
Computing
Z= 748-(2778*0.3)/ √2778*30/100*70/100
z= 748-833.4/√583.38
z= -85.4/24.153
z=-3.5357
Since the calculated z =-3.5357 falls in the critical region z ≥ 1.645 we reject H0 and conclude that the sample provides sufficient evidence to indicate that the true percentage of all firms that announced one or more acquisitions during the year 2000 is ≥ 30%
The p- value is 0.0002
Answer:
Step-by-step explanation:
Let
x ----> the number of 1/3 in that are in 5/6 in
To find out the number of 1/3 in that are in 5/6 in, divide 5/6 by 1/3
so
Multiply in cross
Convert to mixed number
